生成兩個隨機數，再減去他們

Question

我需要做到這一點，我已經想出這個添加：

import random 
mynos = [] 

print ("First, we'll do some addition") 

for counter in range (0,2): 
     mynumber = random.randint(1,20) 
     mynos.append(mynumber) 
print(mynos) 

the_answer = sum(mynos) 
#print(the_answer) (^^^) 

player_answer =int(input("What is the answer?")) 

def main(): 
     if player_answer is the_answer: 
      print ("Correct! Well done!") 
      print ("You scored 1 out of 10 so far!") 
      print ("Good job!") 
     else: 
      print ("Incorrect! You scored null points!") 
      print ("You have zero out of 10 so far!") 
      exit() 

main() 

這是該計劃的增加部分，而不是使用sum有什麼用於減去mynos中的兩個隨機生成的數字？

Answer 1

如果你永遠只能有2個整數，只是用減法上的各個元素：

the_answer = mynos[0] - mynos[1] 

的「功能性」的方式在一個序列中減去的數字是使用reduce() function：

import operator 
try: 
    # Python 3 moved reduce to the functools module 
    from functools import reduce 
except ImportError: 
    pass 

the_answer = reduce(operator.sub, mynos) 

在這種情況下，operator.sub() function代表-運營商。