多COUNT和GROUP BY在一條語句

Question

我使用DISTINCT，LEFT JOIN，COUNT和GROUP BY在單個語句，就像這樣：

SELECT distinct r.sid as sid, s.name as sname, s.image as simage, 
COUNT(r.sid) as scount FROM batch_request r LEFT JOIN student_info s ON s.id = r.sid 
WHERE r.tid='22' group by r.sid 

編碼的JSON是這樣的：

{ "students": 
[ 
{ 
"sid":"1", 
"sname":"Sonali Kohli", 
"simage":"22", 
"scount":"3", 
"sconfirmed":null, 
"sdeclined":null 
}, 
{ 
"sid":"2", 
"sname":"Sona Ali Khan", 
"simage":"22", 
"scount":"3", 
"sconfirmed":null, 
"sdeclined":null 
} 
],"success":1 
} 

表：

正如你可以在上面的圖片查看，我公頃在一個表中共有6條記錄（3對於sid = 1和3對於sid = 2）

sid 1記錄的狀態（2確認[其中值爲1]和1拒絕[其中值爲2]），in同樣的方式sid 2記錄的狀態（1確認[其中值爲1]和2拒絕[其中值爲2]）

同樣的事情我想通過我上面發佈的將QUERY編碼成JSON正如你所看到的，還是我越來越空了兩個JSON對象（即：確認並拒絕）

問題1：應該是什麼的的值and sdeclined for both objects of JSON？

ANSWER 1：在sid = 1情況下（sconfirmed = 2和sdeclined = 1）和用於sid = 2（sconfirmed = 1和sdeclined = 2）

問題2：數據庫表中的sconfirmed和sdeclined是什麼？

答2：sconfirmed只是記錄計數其中狀態是1特定SID和sdeclined是記錄計數其中狀態是2特定SID

Answer 1

嘗試類似這樣：

SELECT distinct r.sid as sid, s.name as sname, s.image as simage, COUNT(r.sid) as scount, 
SUM(CASE r.status WHEN 1 THEN 1 ELSE 0 END) as sconfirmed, 
SUM(CASE r.status WHEN 2 THEN 1 ELSE 0 END) as sdeclined, 
SUM(CASE r.status WHEN 0 THEN 1 ELSE 0 END) as spending 
FROM batch_request r LEFT JOIN student_info s ON s.id = r.sid 
WHERE r.tid='22' 
GROUP BY r.sid