0
我曾試過如下:JPQL:CASE中的布爾表達式何時需要與TRUE/FALSE進行明確比較?
SELECT NEW com.kawoolutions.bbstats.view.ScheduleGameLine(
ga.id AS gid
, ga.scheduledTipoff AS scheduledtipoff
...
, sch.finalScore AS homefinalscore
, sca.finalScore AS awayfinalscore
, CASE WHEN pah.wasWithdrawn OR paa.wasWithdrawn THEN TRUE ELSE FALSE END AS waswithdrawn
)
最後一行是很重要的。據
的情況下是必要的。但是運行這個時候,Hibernate的失敗,
Exception in thread "main" java.lang.IllegalArgumentException: org.hibernate.hql.ast.QuerySyntaxException: unexpected AST node: . near line 19, column 18
at org.hibernate.hql.ast.QuerySyntaxException.convert(QuerySyntaxException.java:54)
at org.hibernate.hql.ast.QuerySyntaxException.convert(QuerySyntaxException.java:47)
at org.hibernate.hql.ast.ErrorCounter.throwQueryException(ErrorCounter.java:82)
at org.hibernate.hql.ast.QueryTranslatorImpl.analyze(QueryTranslatorImpl.java:261)
at org.hibernate.hql.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:185)
at org.hibernate.hql.ast.QueryTranslatorImpl.compile(QueryTranslatorImpl.java:136)
at org.hibernate.engine.query.HQLQueryPlan.<init>(HQLQueryPlan.java:101)
at org.hibernate.engine.query.HQLQueryPlan.<init>(HQLQueryPlan.java:80)
at org.hibernate.engine.query.QueryPlanCache.getHQLQueryPlan(QueryPlanCache.java:124)
at org.hibernate.impl.AbstractSessionImpl.getHQLQueryPlan(AbstractSessionImpl.java:156)
at org.hibernate.impl.AbstractSessionImpl.createQuery(AbstractSessionImpl.java:135)
at org.hibernate.impl.SessionImpl.createQuery(SessionImpl.java:1770)
at org.hibernate.ejb.AbstractEntityManagerImpl.createQuery(AbstractEntityManagerImpl.java:272)
這顯然不是由JPA/Hibernate的語法支持,但Java和數據庫程序員,我期望這樣的表達工作,就像如果(hasHitHard)...和/或SELECT was_withdrawn ...
爲什麼這樣做或爲什麼不支持我所期望的?
看來你沒有完全閱讀我的帖子。當然,AS是支持的。對於你的其他評論請參閱鏈接http://stackoverflow.com/questions/4972369/jpql-hql-and-jpa-hibernate-boolean-expression-in-select-constructor-expression-n ...所以它只是關於 = TRUE/ = FALSE比較。 –
Kawu
2011-02-13 20:32:42