Bash：如何通過插入連續字符和換行符來查找和分解長行？

Question

我知道如何找到排長在一個文件中，用awk或sed的：

$ awk 'length<=5' foo.txt 

將打印長度只有線< = 5

sed -i '/^.\{5,\}$/d' FILE 

將刪除所有行5個以上字符。

但是如何找到長線，然後通過插入連續字符（'&'在我的情況）和換行符來分解它們？

背景：

我有一個自動生成的一些FORTRAN代碼。不幸的是，有些行超過了132個字符的限制。我想找到它們並自動分解它們。例如，這樣的：

this is a might long line and should be broken up by inserting the continuation charater '&' and newline. 

應該成爲這樣的：

this is a might long line and should be broken & 
up by inserting the continuation charater '&' a& 
nd newline. 

Answer 1

一種方式與sed：

$ sed -r 's/.{47}/&\&\n/g' file 
this is a might long line and should be broken & 
up by inserting the continuation charater '&' a& 
nd newline. 

Answer 2

你可以試試：

awk ' 
BEGIN { p=47 } 
{ 
    while(length()> p) { 
     print substr($0,1,p) "&" 
     $0=substr($0,p+1) 
    } 
    print 
}' file 

Answer 3

此解決方案不需要sed或awk。這個很有趣。

tr '\n' '\r' < file | fold -w 47 | tr '\n\r' '&\n' | fold -w 48 

這裏就是你：

this is a might long line and should be broken & 
up by inserting the continuation charater '&' a& 
nd newline. 
But this line should stay intact 
Of course, this is not a right way to do it and& 
you should stick with awk or sed solution 
But look! This is so tricky and fun! 

Answer 4

類似sudo_O的代碼，但這樣做在AWK

awk '{gsub(/.{47}/,"&\\&\n")}1' file