ios將字符串「5小時10分鐘」轉換爲整數小時和分鐘

Question

我想從字符串中獲得小時和分鐘的整數變量「5小時10分鐘」。任何人都可以爲我提供解決方案。

NSString *duration =@"5 hours 10 min"; 

int hours = 5 
int min = 10 

Answer 1

試試這個

- (NSString *)timeFormatted:(int)totalSeconds 
{ 

    int seconds = totalSeconds % 60; 
    int minutes = (totalSeconds/60) % 60; 
    int hours = totalSeconds/3600; 

    return [NSString stringWithFormat:@"%02d:%02d:%02d",hours, minutes, seconds]; 
} 

Answer 2

請嘗試以下的檢索int值碼。

@try { 
    NSString *myString = @"5 hours 10 min"; 
    NSArray *myWords = [myString componentsSeparatedByCharactersInSet: 
         [NSCharacterSet characterSetWithCharactersInString:@" "] 
         ]; 
    int hoursValue = 0, minuteValue = 0; 
    hoursValue = [[myWords objectAtIndex:0] intValue]; 
    if([myWords count] > 2) { 
     minuteValue = [[myWords objectAtIndex:2] intValue]; 
    } 

    NSLog(@"hours %d and Minute %d",hoursValue,minuteValue); 
} 
@catch (NSException * e) { 
    NSLog(@"Exception: %@", e); 
} 

Answer 3

試試這個

@try 
    { 
      NSString *myString = @"5 hours 10 min"; 
      NSArray *myWords = [myString componentsSeparatedByString:@" "]; 
      int hoursValue = 0, minuteValue = 0; 
      if ([myWords count] == 4) 
      { 
       hoursValue = [[myWords objectAtIndex:0] intValue]; 
       minuteValue = [[myWords objectAtIndex:2] intValue]; 

      } 
      else if([myWords count] == 2) 
      { 
       if([[myWords objectAtIndex:1] isEqualToString:@"hours"] == yes) 
       { 
        hoursValue = [[myWords objectAtIndex:0] intValue]; 
       } 
       else 
       { 
        minuteValue = [[myWords objectAtIndex:0] intValue]; 
       } 
      } 
      NSLog(@"hours %d and Minute %d",hoursValue,minuteValue); 
    } 
    @catch(Exception *exception 
    { 
    } 

Answer 4

使用一個NSDateFormatter到字符串1轉換成一個NSDate，然後得到所需的NSDateComponents：

NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init]; 
    [dateFormatter setDateFormat:@"<Date format>"]; 
    NSDate *date = [dateFormatter dateFromString:string1]; 
    NSCalendar *calendar = [NSCalendar currentCalendar]; 
    NSDateComponents *components = [calendar components:(NSCalendarUnitHour | NSCalendarUnitMinute) fromDate:date]; 
    NSInteger hour = [components hour]; 
    NSInteger minute = [components minute]; 

瞭解更多here

Answer 5

試試這個：

int hr,mins; 
NSString *str=@"5 hours 10 min"; 
NSArray *firstWords = [str componentsSeparatedByString:@" "]; 
if (([[firstWords objectAtIndex:1] isEqualToString:@"hours"]||[[firstWords objectAtIndex:1] isEqualToString:@"hr"]) &&([[firstWords objectAtIndex:3] isEqualToString:@"minutes"]||[[firstWords objectAtIndex:3] isEqualToString:@"min"])) { 
    hr=(int)[[firstWords objectAtIndex:0]integerValue]; 
    mins=(int)[[firstWords objectAtIndex:2]integerValue]; 
    if (mins > 60) { 
     hr+=mins/60; 
     mins =mins%60; 

    } 
}