獲取每個品牌的小時銷售sql

Question

我有兩個品牌brand1和brand2我在尋找每個品牌的小時銷量。

我曾嘗試使用下面的查詢來做到這一點，但它返回下面的輸出：

查詢

WITH MyGroupCte 
AS (SELECT 
    OrderDate, 
    Brands.BrandID, 
    Brands.BrandName, 
    SUM((OrderDetails.Quantity * OrderDetails.UnitPrice)) + Orders.DeliveryCharge - ((SUM((OrderDetails.Quantity * OrderDetails.UnitPrice))) * Orders.Discount/100) AS Amount, 
    COUNT(Orders.OrderID) AS Orders 
FROM dbo.Orders 
INNER JOIN dbo.Outlets 
    ON dbo.Orders.OutletID = dbo.Outlets.OutletID 
INNER JOIN dbo.OrderDetails 
    ON dbo.OrderDetails.OrderID = dbo.Orders.OrderID 
INNER JOIN dbo.Brands 
    ON dbo.Brands.BrandID = dbo.Outlets.BrandID 
WHERE dbo.Orders.OrderStatus = 'Closed' 
AND dbo.Orders.OrderDate BETWEEN '06/May/2017 14:00:00.000' AND '06/May/2017 16:00:00.000' 

GROUP BY Orders.OrderID, 
     dbo.Orders.DeliveryCharge, 
     Orders.Discount, 
     Brands.BrandID, 
     Brands.BrandName, 
     Orders.OrderDate) 
SELECT 
    BrandName AS Brand, 
    OrderDate as [Date-Time], 
    COUNT(Orders) AS Orders, 
    SUM(Amount) AS Amount 
FROM MyGroupCte 
GROUP BY OrderDate, 
     BrandName 
ORDER BY Amount DESC 

輸出

Brand Date-Time    Orders Amount 
brand1 2017-05-06 14:04:52.000 1  530.00 
brand1 2017-05-06 14:05:06.000 1  448.00 
brand2 2017-05-06 15:27:21.000 1  347.00 
brand2 2017-05-06 15:52:25.000 1  254.00 
brand2 2017-05-06 16:06:25.000 1  100.00 

取而代之的是我是尋找以下格式的輸出：

Brand Date-Time    Orders Amount 
brand1 2017-05-06 14:00:00.000 2  978.00 
brand2 2017-05-06 15:00:00.000 2  601.00 
brand2 2017-05-06 16:00:00.000 2  100.00 

Answer 1

使用DATEADD(hour, DATEDIFF(hour, 0, OrderDate), 0)可以將日期時間截斷爲小時並將其用於分組。

SELECT 
    BrandName AS Brand, 
    DATEADD(hour, DATEDIFF(hour, 0, OrderDate), 0) as [Date-Time], 
    COUNT(Orders) AS Orders, 
    SUM(Amount) AS Amount 
FROM MyGroupCte 
GROUP BY BrandName, DATEADD(hour, DATEDIFF(hour, 0, OrderDate), 0)