問題與更新mysql數據庫列

-1

你好我無法更新我的MySQL表，當我使用如下SQL：問題與更新mysql數據庫列

if(isset($_POST['submitFeedback'])){ 
     $error = array(); 
     $success = array(); 
     $url = $_SERVER['HTTP_REFERER']; 
     $id = mysql_real_escape_string($_POST['ad_id']); 
     $email = mysql_real_escape_string($_GET['email']); 
     $voted = '1'; 
     if(!isset($_POST['userFeedback'])){ 
     $error[] = 'Please select some feedback'; 
     }else{ 
     if(isset($_POST['subComment'])){ 
      $comment = strtolower(mysql_real_escape_string($_POST['userFeedback'])); 
      $subComment = strtolower(mysql_real_escape_string($_POST['subComment'])); 

      $insertIntoBuyerFeedback = mysql_query("UPDATE buyer_feedback SET 
        seller_vote='$voted', seller_comment='$comment', 
        seller_sub_comment='$subComment', 
       WHERE ad_id='$id' AND buyer_email='$email'") or die(mysql_error()); 
      $success[] = 'Thank you for your feedback!'; 
     } 
     } 
    }

我從瀏覽器

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'WHERE ad_id='5' AND buyer_email='[email protected]'' at line 1

這使得出現以下錯誤對於我來說沒有任何意義，因爲我已經逃脫了有問題的字符串。即使是那些有問題的字符串

來源

2013-07-30 NSaid

多餘的逗號這裏：'... ller_sub_comment = '$ subComment'，' –

擺脫最後更新列（seller_sub_comment）後的額外逗號。

"UPDATE buyer_feedback 
SET seller_vote='$voted',seller_comment='$comment',seller_sub_comment='$subComment' 
WHERE ad_id='$id' AND buyer_email='$email'"

來源

2013-07-30 22:45:28

順便說一句，我建議你使用'$評論= mysql_real_escape_string（用strtolower（$ _ POST [ 'userFeedback']）） ;'而不是'$ comment = strtolower（mysql_real_escape_string（$ _ POST ['userFeedback']））;'以防萬一。 – Muc

爲什麼這應該有所作爲？ – samayo

哈哈，我發誓我試過了 – NSaid

問題與更新mysql數據庫列

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