我在下面的訪問中使用傳遞查詢代碼。代碼不是問題。我的問題是在訪問時創建一個表單,並在指定的地方輸入varible,並從que select SQL select中返回表。常規解決方案:[Form]![Variable]不起作用,因爲傳遞查詢不支持它我想(我不是一個Access專家)。有沒有人有這個問題的解決方案?如何在表單中使用訪問傳遞查詢
SELECT instalacao
,tipounidade
FROM sgdprd.useccionadora us
INNER JOIN (
SELECT bloco
FROM sgdprd.redeprimaria rp
WHERE rp.useccionadora IS NOT NULL CONNECT BY rp.nox = PRIOR rp.fontex
AND rp.noy = PRIOR rp.fontey START
WITH rp.utransformadora = (
SELECT utransformadora
FROM sgdprd.redeprimaria rp
INNER JOIN sgdprd.consumidor con ON rp.utransformadora = con.instalacao
WHERE con.conta = '**VARIABLE GOES HERE**'
)
) lista ON lista.bloco = us.instalacao
WHERE us.tipounidade = 'DJ'
OR us.tipounidade = 'RL'
您的意思是[參數查詢](https://stackoverflow.com/questions/16568461/is-it-possible-to-pass-parameters-programmatically- in-a-microsoft-access-update)?[passthrough query](https://support.office.com/zh-cn/article/Process-SQL-on-a-database-server-by-using-a -pass-through-query-B775AC23-8A6B-49B2-82E2-6DAC62532A42) – BitAccesser