如何通過JavaScript

Question

從數據庫中獲取下拉值這個代碼用在這個代碼下拉列表中值來創建表&動態記錄應該從數據庫中感到請告訴我如何填寫下拉此代碼

<script type="text/javascript"> 
$(document).ready(function(){ 
    $(".add-row").click(function(){ 

     // var markup = "<tr><td><input type='checkbox' name='record'></td><td><input type='text' name=''></td><td><input type='text' name=''></td><td><input type='text' name=''></td><td><input type='text' name=''></td><td><input type='text' name=''></td><td><input type='text' name=''></td>"; 
     var markup = "<tr class='item-row'><td align='center'>"+ 
       "<input name='record' type='checkbox'>"+ 
       "</td> <td align='center'>"+ 
       "<div class='form-group'>"+ 
        "<select name='item_select1' id='item_select1' class='form-control' onchange='item_value();'>"+ 
        "<option value='' disabled selected>---Select---</option>"+ 
        "<option value='1'>+Add New Item</option>"+ 
       "</select><br />"+ 
       "<textarea id='item_description' name='item_description'></textarea></div></td>"+ 
       "<td align='center'><input type='text' class='form-control' name='item_unit' id='item_unit' placeholder='Display Name ...'></td>"+   
      "<td align='center'><input type='text' class='form-control' name='item_rate' id='item_rate' placeholder='Display Name ...'></td> "+     
       "<td align='center'><input type='text' class='form-control' name='item_discount' id='item_discount' placeholder='Discount %'></td>"+     
      "<td align='center'><div class='form-group'>"+ 
        "<select name='item_tax_id1' id='item_tax_id1' class='form-control' onchange='tax_value();'>"+ 
        "<option value='' disabled selected>---Select---</option>"+ 
        "<option value=''>+Add New Item</option></select></div></td>"+ 
        "<td align='center'><label name='item_amount' id='item_amount'></label></td></tr>"; 
     $("table tbody").append(markup); 
    }); 

    // Find and remove selected table rows 
    $(".delete-row").click(function(){ 
     $("1 tbody").find('input[name="record"]').each(function(){ 
      if($(this).is(":checked")){ 
       $(this).parents("tr").remove(); 
      } 
     }); 
    }); 
});  

Answer 1

你可以嘗試這樣的

$.ajax({ 
     type: "POST", 
     url: url, 
     contentType: "application/json; charset=utf-8", 
     async: false, 
     data: data, 
     dataType: "json", 
     success: function (json) { 
      $.each(json, function (index, elem) { 
      $("#drpId").append("<option value=\"" + elem.value+ "\">" + elem.name+ "</option>"); 
     }); 
      } 
     }, 
     error: function (errMsg) { 

     } 
    });