2017-04-03 80 views
0

我有兩個查詢,每個都返回從一堆其他表中的數據派生的相當複雜的表,並且我想將它們連接在一起,然後在超級連接的表上使用一個組。SQL - 連接兩個派生表

我不認爲我可以用單個查詢來派生此表,因爲每個人訪問一組不同的表,並且排序的故事是無法將所有需要的信息都加入到單個查詢中行(至少我想不出一種方式)。

第一個查詢是:

select 
    pr.runName, 
    cp.firstname, 
    mp.name 
from 
    passrun as pr, 
    passrunpoly as prp, 
    mappolygon as mp, 
    cmnemployee as ce, 
    cmnperson as cp, 
    passschedule as ps 

where 
    pr.runid = prp.runid 
    and prp.polyid = mp.polyid 
    and pr.employeeid = ce.employeeid 
    and ce.personid = cp.personid 
    and pr.scheduleid = ps.scheduleid 
    and ps.ldate = 20170403 

第二個查詢是:

select 
    mp.name, 
    count(distinct pbl.lat) as Stops, 
    count(case when pba.spacetype = 'S' then pb.ldate end)/2 as S, 
    count(case when pba.spacetype = 'WC' then pb.ldate end)/2 as WC, 
    count(case when pba.spacetype = 'WK' then pb.ldate end)/2 as WK 
from 
    passbookingactivity as pba, 
    passbooking as pb, 
    passbookingleg as pbl, 
    mappolygon as mp 
where 
    pb.bookingid = pba.bookingid 
    and pb.bookingid = pbl.bookingid 
    and mp.polyid = pbl.addresspolygonid 
    and pb.ldate = 20170403 
    and pb.servicetypeid = 5 
group by mp.name, mp.abbreviation 

我想沿着mp.name加入這些,然後按pr.runname,cp.firstname, mp.name

+0

我推薦現代連接語法。 – Degan

回答

0

雖然我沒有讓這太漂亮,但這應該可以做到。 讓我知道它是怎麼回事!

select 
a.runname 
,a.firstname 
, a.name 
from 
(select 
    pr.runName, 
    cp.firstname, 
    mp.name 
from 
    passrun as pr, 
    passrunpoly as prp, 
    mappolygon as mp, 
    cmnemployee as ce, 
    cmnperson as cp, 
    passschedule as ps 

where 
    pr.runid = prp.runid 
    and prp.polyid = mp.polyid 
    and pr.employeeid = ce.employeeid 
    and ce.personid = cp.personid 
    and pr.scheduleid = ps.scheduleid 
    and ps.ldate = 20170403)a 
inner join (
select 
    mp.name, 
    count(distinct pbl.lat) as Stops, 
    count(case when pba.spacetype = 'S' then pb.ldate end)/2 as S, 
    count(case when pba.spacetype = 'WC' then pb.ldate end)/2 as WC, 
    count(case when pba.spacetype = 'WK' then pb.ldate end)/2 as WK 
from 
    passbookingactivity as pba, 
    passbooking as pb, 
    passbookingleg as pbl, 
    mappolygon as mp 
where 
    pb.bookingid = pba.bookingid 
    and pb.bookingid = pbl.bookingid 
    and mp.polyid = pbl.addresspolygonid 
    and pb.ldate = 20170403 
    and pb.servicetypeid = 5 
group by mp.name, mp.abbreviation)b 
on a.name = b.name 
group by a.runname,a.firstname, a.name 
0

您可以使用公用表表達式(我也改變你的加入語法):

with table_one as (
select 
    pr.runName, 
    cp.firstname, 
    mp.name 
from 
    passrun as pr 
    inner join passrunpoly as prp on pr.runid = prp.runid 
    inner join mappolygon as mp on prp.polyid = mp.polyid 
    inner join cmnemployee as ce on pr.employeeid = ce.employeeid 
    inner join cmnperson as cp on ce.personid = cp.personid 
    inner join passschedule as ps on pr.scheduleid = ps.scheduleid 
where 
    ps.ldate = 20170403 

), table_two as (

select 
    mp.name, 
    count(distinct pbl.lat) as Stops, 
    count(case when pba.spacetype = 'S' then pb.ldate end)/2 as S, 
    count(case when pba.spacetype = 'WC' then pb.ldate end)/2 as WC, 
    count(case when pba.spacetype = 'WK' then pb.ldate end)/2 as WK 
from 
    passbookingactivity as pba 
    passbooking as pb on pb.bookingid = pba.bookingid 
    passbookingleg as pbl on pb.bookingid = pbl.bookingid 
    mappolygon as mp on mp.polyid = pbl.addresspolygonid 
where 
    pb.ldate = 20170403 
    and pb.servicetypeid = 5 
group by mp.name, mp.abbreviation 
) 

select 
    one.runname, 
    one.name, 
    one.firstname 
from table_one one 
    inner join table_two two on one.name = two.name 
group by one.runname,one.name,one.firstname