2012-07-02 89 views
8

我正在試驗AudioTrack類。基本上,我的應用程序必須在用戶觸摸屏幕上的特定對象時生成聲音。我用this example作爲指導。
我的應用程序似乎工作,因爲它應該,但通常觸摸屏幕約一分鐘後,它崩潰了:
從生成類AudioTrack:play()對未初始化的AudioTrack調用

07-02 20:40:53.459: E/AndroidRuntime(11973): FATAL EXCEPTION: Thread-10 
07-02 20:40:53.459: E/AndroidRuntime(11973): java.lang.IllegalStateException: play() called on uninitialized AudioTrack. 
07-02 20:40:53.459: E/AndroidRuntime(11973): at android.media.AudioTrack.play(AudioTrack.java:824) 
07-02 20:40:53.459: E/AndroidRuntime(11973): at com.mysounds_experimental.SoundThread.playSound(SoundThread.java:108) 
07-02 20:40:53.459: E/AndroidRuntime(11973): at com.mysounds_experimental.SoundThread.run(SoundThread.java:69) 

方法聽起來

public void initAudioTrack() { 
     int bufferSize = AudioTrack.getMinBufferSize(sampleRate 
       , AudioFormat.CHANNEL_CONFIGURATION_MONO, AudioFormat.ENCODING_PCM_16BIT); 

     audioTrack = new AudioTrack(
       AudioManager.STREAM_MUSIC 
       , sampleRate 
       , AudioFormat.CHANNEL_CONFIGURATION_MONO 
       , AudioFormat.ENCODING_PCM_16BIT 
       , bufferSize 
       , AudioTrack.MODE_STREAM); 
    } 

    private void playSound(){ 
      audioTrack.write(generatedSnd, 0, numSamples); 
      audioTrack.play(); 
     } 

public void stopPlaying() { 
    audioTrack.flush(); 
    audioTrack.stop(); 
    audioTrack.release(); 
} 

@Override 
    public void run() { 
     while (mRun) { 
      try{ 
       Thread.sleep(200); 
       while(soundCycle){ 
        if(freqOfTone != -1f) { 
         generateTone(); 
         playSound(); 
         Thread.sleep(200); 
        } 
       } 
      } catch(InterruptedException e){ 
       //    soundCycle = false; 
       //    soundPool.stop(BEEP); 
      } 
     } 
    } 

這是一個方法自定義查看我的線程

@Override 
    public boolean onTouchEvent(final MotionEvent ev) { 
     int currentXPosition = (int) ev.getX(); 
     int currentYPosition = (int) ev.getY(); 

     if(ev.getX() < smBitmap.getWidth()) 
      if(ev.getY() < smBitmap.getHeight()){ 
       tempCol = smBitmap.getPixel(currentXPosition, currentYPosition); 
      } 

     final int action = ev.getAction(); 

     switch (action & MotionEvent.ACTION_MASK) { 

     case MotionEvent.ACTION_DOWN: { 

      sThread.freqOfTone = getFreqPreset(tempCol); 
      if(col != tempCol){ 
//    sThread.initAudioTrack(); 
       sThread.interrupt(); 
       if(shouldInit) { 
        shouldInit = false; 
        sThread.initAudioTrack(); 
       } 
       sThread.soundCycle = true; 
       col = tempCol; 
       invalidate(); 
      } 
      break; 
     } 

     case MotionEvent.ACTION_MOVE: { 
      sThread.freqOfTone = getFreqPreset(tempCol); 

      if (tempCol == -1 || tempCol == 0) { 
       sThread.soundCycle = false; 
       shouldInit = true; 
//    sThread.stopPlaying(); 
       sThread.interrupt(); 
       invalidate(); 
      } else { 
       if(col != tempCol){ 
        sThread.interrupt(); 
        col = tempCol; 
        invalidate(); 
       }else { 
        sThread.soundCycle = true; 
        col = tempCol; 
        invalidate(); 
       } 
      } 
      break; 
     }// case ACTION_MOVE 

     case MotionEvent.ACTION_UP: { 
      sThread.soundCycle = false; 
      shouldInit = true; 
//   sThread.stopPlaying(); 
      sThread.interrupt(); 
      col = -1; 
      mActivePointerId = INVALID_POINTER_ID; 
      break; 
     }// case ACTION_UP 

     } 

     return true; 
    } 

任何想法w hy這是怎麼回事?

+0

'// sThread.initAudioTrack();'取消這個 –

+0

我說取消註釋,不刪除 –

+0

對不起,我的意思是說取消註釋。 – droid8421

回答

0

我想你需要致電play(),然後再致電write()

但我也注意到,當你創建大量AudioTrack情況下,即使你認爲你清理了一切寫,有時play()無法工作,並且曲目初始化。

你會想嘗試...趕上這IllegalStateException,並避免撥打write(),直到play()工作,而不會引發異常。

1

爲什麼你註釋掉了你的stopPlaying()方法?

您只能創建32個AudioTracks。如果你想要更多,你應該調用release()方法。