串聯列有不同的值在Oracle

Question

大師，

我的表結構法看起來像follwoing：

TankListUS TankListCanada  TankListIndia 
---------- --------------  ------------- 
T111||T222 T444||T222   T555 

現在，當我運行查詢：

select (TL.TankListUS || '||' || TL.TankListCanada || '||' || TL.TankListIndia)as "OverallSummary" from TankListTL 

我得到的輸出

T111||T222||T444||T222||T555 

但我不知道不需要重複坦克。我需要我的輸出爲：

T111||T222||T444||T555 

這可能嗎？

Answer 1

我沒有測試過這一點，但嘗試以下操作： -

with test1 as 
(select (TL.TankListUS || '||' || TL.TankListCanada || '||' || TL.TankListIndia) as str from TankListTL), 
test2 as 
(select regexp_substr(str,'[^|]+',1,rownum) split 
from test1 
connect by level <= length (regexp_replace (str, '[^|]+')) + 1) 
select listagg(split,'||') within group(order by split) 
from test2 

請注意，LISTAGG在甲骨文11gR2的介紹。以下是一些字符串匯聚技術： -

http://www.oracle-base.com/articles/misc/string-aggregation-techniques.php#listagg

Answer 2

來源：

TANKLISTUS TANKLISTCANADA TANKLISTINDIA 
T111||T222 T444||T222  T555 
T111||T222 T444||T111  T555 
T111||T666 T444||T222  T555 

代碼：

WITH src AS 
(
     SELECT 'T111||T222' TankListUS, 'T444||T222' TankListCanada, 'T555' TankListIndia FROM DUAL UNION ALL 
     SELECT 'T111||T222' TankListUS, 'T444||T111' TankListCanada, 'T555' TankListIndia FROM DUAL UNION ALL 
     SELECT 'T111||T666' TankListUS, 'T444||T222' TankListCanada, 'T555' TankListIndia FROM DUAL 
) 
, step1 AS 
(
     SELECT SUBSTR(TankListUS,  1, 4) AS us1 
     ,  SUBSTR(TankListUS,  7) AS us2 
     ,  SUBSTR(TankListCanada, 1, 4) AS ca1 
     ,  SUBSTR(TankListCanada, 7) AS ca2 
     ,  TankListIndia    AS in1 
     ,  ROWNUM AS r_id 
     FROM src 
) 
, step2 AS 
(
     SELECT us1 AS r_value, r_id FROM step1 UNION 
     SELECT us2, r_id FROM step1 UNION 
     SELECT ca1, r_id FROM step1 UNION 
     SELECT ca2, r_id FROM step1 UNION 
     SELECT in1, r_id FROM step1 
) 
,step3 AS 
(
     SELECT r_value 
     ,  LEAD(r_value, 1) OVER (PARTITION BY r_id ORDER BY r_value) AS lead1 
     ,  LEAD(r_value, 2) OVER (PARTITION BY r_id ORDER BY r_value) AS lead2 
     ,  LEAD(r_value, 3) OVER (PARTITION BY r_id ORDER BY r_value) AS lead3 
     ,  LEAD(r_value, 4) OVER (PARTITION BY r_id ORDER BY r_value) AS lead4 
     ,  ROW_NUMBER()  OVER (PARTITION BY r_id ORDER BY r_value) AS r_num 
     FROM step2 
) 
,step4 AS 
(
     SELECT r_value 
     ||  NVL2(lead1, '||' || lead1, lead1) 
     ||  NVL2(lead2, '||' || lead2, lead2) 
     ||  NVL2(lead3, '||' || lead3, lead3) 
     ||  NVL2(lead4, '||' || lead4, lead4) AS the_result 
     FROM step3 
     WHERE r_num = 1 
) 
-- OR: 
SELECT DISTINCT the_result AS the_result_with_DISTINCT 
FROM step4 

結果：

T111||T222||T444||T555||T666 
T111||T222||T444||T555 

Answer 3

with t1 as (select 'T111||T222||T444||T222||T555' col from dual), 

t2 as (SELECT rownum,REGEXP_SUBSTR (col, '[^||]+', 1, RN) SPLIT 

from t1 
cross join 

(SELECT ROWNUM RN 

FROM (SELECT (length(REGEXP_REPLACE (col, '[^||]+'))/2)+1 MAX_VALUE 

from t1) 

connect by level <= max_value)), 

t3 as (select distinct split as dis_col from t2) 

select 

    rtrim (xmlagg (xmlelement (e, dis_col || '||')).extract ('//text()'), '||') d_col 

from 

    t3;