轉換列排在Oracle

這是我在Oracle 11g中表：轉換列排在Oracle

**date   qty1   qty2    qty3   qty4** 
2-Feb-14   61   64    52   54 
2-Mar-14   124   130   149   156

我想將其轉換成下表。即在日期中添加7天並轉換數量。我有直到qty52這樣的度量

***date  qty*** 
**2-Feb-14  61** 
9-Feb-14   64 
16-Feb-14   52 
23-Feb-14   54 
**2-Mar-14  124** 
9-Mar-14   130 
16-Mar-14   149 
23-Mar-14   156

來源

2014-01-09 user3176209

搜索支點。 – haki

select date,qty from 
(select date,qty1 as qty 
from tbl 
union 
select date+7 as date,qty2 as qty 
from tbl 
union 
select date+14 as date,qty3 as qty 
from tbl 
union 
select date+21 as date,qty4 as qty 
from tbl) 
order by date

來源

2014-01-09 06:29:00 dpk

謝謝你們！所有的建議工作！ – user3176209

試一試：

WITH t(my_date, val, val2, val3, val4) 
AS ( 
SELECT to_date('01/01/2014 12:00:00 AM', 'dd/mm/yyyy hh:mi:ss am'), 1,2,3,4 from dual 
UNION ALL 
SELECT to_date('01/02/2014 12:00:00 AM', 'dd/mm/yyyy hh:mi:ss am'), 5,6,7,8 FROM dual 
) 
SELECT (my_date-7) + (row_number() OVER (partition by my_date ORDER BY my_date)*7) my_date, value as qty 
FROM (
    (SELECT my_date, val, val2, val3, val4 FROM t 
    ) unpivot (value FOR value_type IN (val, val2, val3, val4)));

輸出：

MY_DATE      QTY 
----------------------- ---------- 
01/01/2014 12:00:00 AM   1 
08/01/2014 12:00:00 AM   2 
15/01/2014 12:00:00 AM   3 
22/01/2014 12:00:00 AM   4 
01/02/2014 12:00:00 AM   5 
08/02/2014 12:00:00 AM   6 
15/02/2014 12:00:00 AM   7 
22/02/2014 12:00:00 AM   8

來源

2014-01-09 06:27:47 ajmalmhd04

試試這個

with tab(date_d,qty1,qty2,qty3,qty4) as (
    select '2-Feb-14',61,64,52,54 from dual union all 
    select '2-Mar-14',124,130,149,156 from dual), 
tab2(dd, ss) as (select date_d, qty1||','||qty2||','||qty3||','||qty4 from tab) 
select to_date(dd) + ((level-1) * 7) "DATE", regexp_substr(ss, '[^(,)]+', 1, level) "QTY" 
    from tab2 
connect by level <= length(ss) - length(replace(ss, ',')) + 1 
    and prior ss = ss 
    and prior sys_guid() is not null

輸出

|       DATE | QTY | 
|---------------------------------|-----| 
| March, 02 2014 00:00:00+0000 | 124 | 
| March, 09 2014 00:00:00+0000 | 130 | 
| March, 16 2014 00:00:00+0000 | 149 | 
| March, 23 2014 00:00:00+0000 | 156 | 
| February, 02 2014 00:00:00+0000 | 61 | 
| February, 09 2014 00:00:00+0000 | 64 | 
| February, 16 2014 00:00:00+0000 | 52 | 
| February, 23 2014 00:00:00+0000 | 54 |

讓我知道它是否符合您的要求。

來源

2014-01-09 06:37:36 San

如果你有Oracle 11g，我會考慮使用UNPIVOT來完成。

select 
    start_date + to_number(week_number) * 7, 
qty 
from (
    select * 
    from quantity_data 
    unpivot (qty for week_number 
      in (qty1 as '0', qty2 as '1', qty3 as '2', qty4 as '3')) 
)

這是來自ajmalmhd04的示例的替代方法，它使用to_number而不是row_number分析函數。從ajmalmhd04答案可能是，雖然

更通用的。如果你還沒有那麼的Oracle 11g嘗試一下本作的一個選項：

with pivot_data as (
    select 0 as pivot_col from dual union all 
    select 1 from dual union all 
    select 2 from dual union all 
    select 3 from dual 
) 
select 
    start_date + (7 * pivot_col) as start_date, 
    case 
    when pivot_col = 0 then qty1 
    when pivot_col = 1 then qty2 
    when pivot_col = 2 then qty3 
    when pivot_col = 3 then qty4 end as qty 
from 
    quantity_data cross join pivot_data 
order by 1

來源

2014-01-09 06:44:06

轉換列排在Oracle

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