在oracle中結轉列值

-4

我有兩個表TableA和TableB。兩者都有相同的列。我想用TableB的VALUE列值更新TableA的VALUE列值。在oracle中結轉列值

這是我的表結構。

表A

Date  Value 
7/6/2015 0 
7/5/2015 0 
7/4/2015 0 
7/3/2015 0 
7/2/2015 0 
7/1/2015 100

表B

Date  Value 
7/3/2015 2 
7/1/2015 3

如果表A的值列不具有任何值，那麼我們必須更新TableA->使用TableB- VALUE> VALUE +最少日期值（100）。這裏TableA的最小日期值是100.所以我需要TableA中的值（100 + tableB-> VALUE）。

TableA. 
Date  Value 
7/6/2015 105 Carry forward the last value of this column 
7/5/2015 105 Carry forward the last value of this column 
7/4/2015 105 Carry forward the last value of this column 
7/3/2015 105 103+2(VALUE of TableB) 
7/2/2015 103 Carry forward the last value of this column 
7/1/2015 103 (100 +3(VALUE of TableB)

根據條件繼續列值。

請儘快給我查詢。

感謝，

來源

2015-07-06 user2982630

**請儘快給我查詢。**？ –

這可能是你追求的：

with tablea as (select to_date('06/07/2015', 'dd/mm/yyyy') dt, 0 value from dual union all 
       select to_date('05/07/2015', 'dd/mm/yyyy') dt, 0 value from dual union all 
       select to_date('04/07/2015', 'dd/mm/yyyy') dt, 0 value from dual union all 
       select to_date('03/07/2015', 'dd/mm/yyyy') dt, 0 value from dual union all 
       select to_date('02/07/2015', 'dd/mm/yyyy') dt, 0 value from dual union all 
       select to_date('01/07/2015', 'dd/mm/yyyy') dt, 100 value from dual), 
    tableb as (select to_date('03/07/2015', 'dd/mm/yyyy') dt, 2 value from dual union all 
       select to_date('01/07/2015', 'dd/mm/yyyy') dt, 3 value from dual) 
select ta.dt, 
     last_value(decode(ta.value, 0, null, ta.value) ignore nulls) over (order by ta.dt) 
     + sum(tb.value) over (order by ta.dt) new_value 
from tablea ta 
     left outer join tableb tb on (ta.dt = tb.dt) 
order by ta.dt desc; 

DT   NEW_VALUE 
---------- ---------- 
06/07/2015  105 
05/07/2015  105 
04/07/2015  105 
03/07/2015  105 
02/07/2015  103 
01/07/2015  103

但是，你不說經過一系列的零時，有一個在一個非零值，會發生什麼價值觀，很難說這是否會按照你在這種情況下的預期行事。例如，使用相同的數據，但tablea.value = 200爲7月4日：

with tablea as (select to_date('06/07/2015', 'dd/mm/yyyy') dt, 0 value from dual union all 
       select to_date('05/07/2015', 'dd/mm/yyyy') dt, 0 value from dual union all 
       select to_date('04/07/2015', 'dd/mm/yyyy') dt, 0 value from dual union all 
       select to_date('03/07/2015', 'dd/mm/yyyy') dt, 200 value from dual union all 
       select to_date('02/07/2015', 'dd/mm/yyyy') dt, 0 value from dual union all 
       select to_date('01/07/2015', 'dd/mm/yyyy') dt, 100 value from dual), 
    tableb as (select to_date('03/07/2015', 'dd/mm/yyyy') dt, 2 value from dual union all 
       select to_date('01/07/2015', 'dd/mm/yyyy') dt, 3 value from dual) 
select ta.dt, 
     last_value(decode(ta.value, 0, null, ta.value) ignore nulls) over (order by ta.dt) 
     + sum(tb.value) over (order by ta.dt) new_value 
from tablea ta 
     left outer join tableb tb on (ta.dt = tb.dt) 
order by ta.dt desc; 

DT   NEW_VALUE 
---------- ---------- 
06/07/2015  205 
05/07/2015  205 
04/07/2015  205 
03/07/2015  105 
02/07/2015  103 
01/07/2015  103

你必須更新你的問題涵蓋所有情形，如果我的查詢不會對你以後是什麼和你不能自己解決如何修改它。

來源

2015-07-06 11:22:11 Boneist

在oracle中結轉列值

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