MySQL不捕捉錯誤

Question

爲什麼當我嘗試刪除不存在的行時，此代碼沒有捕捉到錯誤？無論我將哪個參數作爲行的名稱傳入，它總是返回「1行刪除」，並且不使用退出處理程序。這應該只是捕捉這種類型的錯誤。

USE yoga; 

DROP PROCEDURE IF EXISTS delete_warmup; 

DELIMITER // 

CREATE PROCEDURE delete_warmup 
(
    warmup_name_param    VARCHAR(100) 
) 
BEGIN 
DECLARE row_not_found  TINYINT DEFAULT FALSE; 
DECLARE sql_exception  TINYINT DEFAULT FALSE; 

BEGIN 
    DECLARE EXIT HANDLER FOR 1329 
     SET row_not_found = TRUE; 
    DECLARE EXIT HANDLER FOR SQLEXCEPTION 
     SET sql_exception = TRUE; 

    DELETE FROM warmup 
    WHERE warmup_name = warmup_name_param; 

    SELECT '1 row was deleted.' AS message; 
END; 

IF row_not_found = TRUE THEN 
    SELECT 'Row not deleted - row not found' AS message; 
ELSEIF sql_exception = TRUE THEN 
    SHOW ERRORS; 
END IF; 

END// 

DELIMITER ; 

CALL delete_warmup ('Monkey business'); 

Answer 1

您使用的是退出處理的重複的參數：http://www.briandunning.com/errors/596爲您指定

也許你應該嘗試錯誤代碼1011爲1329：http://www.briandunning.com/errors/278

另外，嘗試尋找NOT FOUND以及as SQLException

另外，嘗試將exit處理程序放在begin/end子句之外。

所以你BEGIN和END條款是

DECLARE EXIT HANDLER FOR 1011 
DECLARE EXIT HANDLER FOR SQLEXCEPTION, NOT FOUND 
BEGIN 
     SET row_not_found = TRUE; 
     SET sql_exception = TRUE; 

    DELETE FROM warmup 
    WHERE warmup_name = warmup_name_param; 

    SELECT '1 row was deleted.' AS message; 
END;