如何從MySQL日期提取年，月，日，時，分，秒？

Question

在我的mysql數據庫中我有這樣的日期：2011-01-06 09：39：114525

我需要extraxt分別年，月，日，小時，分鐘，秒從它。

所以我需要從上面的例子中提取：

2011 
01 
06 
09 
39 
11 

我該怎麼辦呢？

Answer 1

在MySQL中，只要執行MONTH(date),等。在PHP中，您可以執行date('g', strtotime($datefromsql))以獲取例如從日期開始的12小時格式小時。

因此，在你上面的例子中，你既可以做

SELECT YEAR(date), 
     MONTH(date), 
     DAYOFMONTH(date), 
     HOUR(date), 
     MINUTE(date), 
     SECOND(date) 

或PHP，

$time = strtotime($datefromsql); 
echo date('Y', $time); 
echo date('m', $time); 
echo date('d', $time); 
echo date('h', $time); 
echo date('i', $time); 
echo date('s', $time); 

Answer 2

檢查此鏈接http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html

ADDDATE() Add time values (intervals) to a date value 

ADDTIME() Add time 

CONVERT_TZ() Convert from one timezone to another 

CURDATE() Return the current date 

CURRENT_DATE(), CURRENT_DATE Synonyms for CURDATE() 

CURRENT_TIME(), CURRENT_TIME Synonyms for CURTIME() 

CURRENT_TIMESTAMP(), CURRENT_TIMESTAMP Synonyms for NOW() 

CURTIME() Return the current time 

DATE_ADD() Add time values (intervals) to a date value 

DATE_FORMAT() Format date as specified 

DATE_SUB() Subtract a time value (interval) from a date 

DATE() Extract the date part of a date or datetime expression 

DATEDIFF() Subtract two dates 

DAY() Synonym for DAYOFMONTH() 

DAYNAME() Return the name of the weekday 

DAYOFMONTH() Return the day of the month (0-31) 

DAYOFWEEK()  Return the weekday index of the argument 

DAYOFYEAR()  Return the day of the year (1-366) 

EXTRACT() Extract part of a date 

FROM_DAYS()  Convert a day number to a date 

FROM_UNIXTIME()  Format UNIX timestamp as a date 

GET_FORMAT() Return a date format string 

HOUR() Extract the hour 

LAST_DAY Return the last day of the month for the argument 

LOCALTIME(), LOCALTIME Synonym for NOW() 

LOCALTIMESTAMP, LOCALTIMESTAMP() Synonym for NOW() 

MAKEDATE() Create a date from the year and day of year 

MAKETIME MAKETIME() 

MICROSECOND() Return the microseconds from argument 

MINUTE() Return the minute from the argument 

MONTH()  Return the month from the date passed 

MONTHNAME()  Return the name of the month 

NOW() Return the current date and time 

PERIOD_ADD() Add a period to a year-month 

PERIOD_DIFF() Return the number of months between periods 

QUARTER() Return the quarter from a date argument 

SEC_TO_TIME() Converts seconds to 'HH:MM:SS' format 

SECOND() Return the second (0-59) 

STR_TO_DATE() Convert a string to a date 

SUBDATE() A synonym for DATE_SUB() when invoked with three arguments 

SUBTIME() Subtract times 

SYSDATE() Return the time at which the function executes 

TIME_FORMAT() Format as time 

TIME_TO_SEC() Return the argument converted to seconds 

TIME() Extract the time portion of the expression passed 

TIMEDIFF() Subtract time 

TIMESTAMP()  With a single argument, this function returns the date or datetime expression; with two arguments, the sum of the arguments 

TIMESTAMPADD() Add an interval to a datetime expression 

TIMESTAMPDIFF()  Subtract an interval from a datetime expression 

TO_DAYS() Return the date argument converted to days 

TO_SECONDS() Return the date or datetime argument converted to seconds since Year 0 

UNIX_TIMESTAMP() Return a UNIX timestamp 

UTC_DATE() Return the current UTC date 

UTC_TIME() Return the current UTC time 

UTC_TIMESTAMP()  Return the current UTC date and time 

WEEK() Return the week number 

WEEKDAY() Return the weekday index 

WEEKOFYEAR() Return the calendar week of the date (0-53) 

YEAR() Return the year 

YEARWEEK() Return the year and week 

Answer 3

使用DateTime類

的最佳方式

$my_sql_date = '2011-01-06 09:39:11'; 
$date_time = new DateTime($my_sql_date); 
echo $date_time->format('Y').PHP_EOL; 
echo $date_time->format('m').PHP_EOL; 
echo $date_time->format('d').PHP_EOL; 
echo $date_time->format('h').PHP_EOL; 
echo $date_time->format('i').PHP_EOL; 
echo $date_time->format('s'); 

Answer 4

$dt = Carbon::now(); 
$dt->timestamp = strtotime($mysqlVarDatetime); //like '2017-01-31 07:19:11' string cad 

可以導致：

var_dump($dt->year);           // int(2017) 
var_dump($dt->month);          // int(1) 
var_dump($dt->day);           // int(31) 
var_dump($dt->hour);           // int(7) 
var_dump($dt->minute);          // int(19) 
var_dump($dt->second);          // int(11) 

資源以獲取更多信息碳庫：http://carbon.nesbot.com/docs/#api-getters

Answer 5

舊線，但我無法抗拒張貼明顯的「蠻力'解決方案：

如果您的SQL日期時間字符串格式總是在您的示例中給出，並且您不想使用日期時間函數/ cl驢，你可以做到以下幾點：

$mysql_datetime = "2011-01-06 09:39:114525"; 
list($date, $time) = explode(' ', $mysql_datetime); 
list($year, $month, $day) = explode('-', $date); 
list($hr, $min, $sec) = explode(':', $time); 
$sec = (int)substr($sec, 0, 2); 

你想要的值現在可以在以下變量：$year, $month, $day, $hr, $min, $sec。