我有2個表:的Python/SQLITE3:LEFT JOIN與GROUP_CONCAT
Tasks: Predecessors:
ID | Task | Team ID | TaskID | PredecessorID
---+------+------ ---+--------+--------------
1 | A | 1 1 | 1 | None
2 | B | 1 2 | 2 | 1
3 | C | 2 3 | 3 | 1
4 | D | 2 4 | 3 | 2
5 | 4 | None
我想選擇全部來自二隊任務,並添加前輩們通過這種形式逗號分隔每個任務:
ID | Task | Team | Predecessors
---+------+------+-------------
3 | C | 2 | 1, 2
4 | D | 2 | None
所以我用下面的SQL查詢:
SELECT Tasks.*, GROUP_CONCAT(Predecessors.PredecessorID)
FROM Tasks LEFT JOIN Predecessors ON Tasks.ID = Predecessors.TaskID
WHERE Tasks.Team = 2 GROUP BY Predecessors.TaskID
返回:
ID | Task | Team | Predecessors
---+------+------+-------------
3 | C | 2 | 1, 2
我能做些什麼來獲得獲得與無價值也行?
這裏是我的測試代碼:
# -*- coding: utf-8 -*-
import sqlite3
con = sqlite3.connect('test.db')
cur = con.cursor()
# Drop old tables if they already exits and create new ones. (For testing).
cur.execute("""DROP TABLE IF EXISTS Tasks""")
cur.execute("""DROP TABLE IF EXISTS Predecessors""")
# Create tables.
cur.execute("""CREATE TABLE Tasks (ID INTEGER PRIMARY KEY AUTOINCREMENT,
Task TEXT, Team INTEGER)""")
cur.execute("""CREATE TABLE Predecessors (ID INTEGER PRIMARY KEY AUTOINCREMENT,
TaskID INTEGER, PredecessorID INTEGER)""")
# Insert some values.
sql = """INSERT INTO Tasks (Task, Team) VALUES (?, ?)"""
for task in [('A', 1), ('B', 1), ('C', 2), ('D', 3)]:
cur.execute(sql, task)
sql = """INSERT INTO Predecessors (TaskID, PredecessorID) VALUES (?, ?)"""
for predecessor in [(1, None), (2, 1), (3, 1), (3, 2), (4, None)]:
cur.execute(sql, predecessor)
con.commit()
sql = """SELECT Tasks.*, GROUP_CONCAT(Predecessors.PredecessorID)
FROM Tasks LEFT JOIN Predecessors ON Tasks.ID = Predecessors.TaskID
WHERE Tasks.Team = 2 GROUP BY Predecessors.TaskID"""
cur.execute(sql)
data = cur.fetchall()
print data
con.close()
感謝您的幫助!
謝謝!你介意給我寫整個查詢嗎? (因爲我以前從未使用GROUP BY語句,並且不知道確切位置在我的查詢中) –
只需將其替換即可。 –
對不起,我沒有仔細閱讀你的答案。我以爲我應該使用GROUP BY語句而不是GROUP_CONCAT。那是垃圾。 GROUP BY聲明解決了我的實際問題!而obgnaws的答案也是正確的。 –