我遇到了Zend框架和數據庫連接的問題,我試圖創建一個登錄名,表被創建,並且代碼顯然是好的,但給我這個:Zend錯誤SQLSTATE [HY000] [1045]
An error occurred
Application error
Exception information:
Message: SQLSTATE[HY000] [1045] Access denied for user 'onetag51_teste'@'localhost' (using password: YES)
Stack trace:
#0 C:\xampp\Zend\library\Zend\Db\Adapter\Pdo\Mysql.php(109): Zend_Db_Adapter_Pdo_Abstract->_connect()
#1 C:\xampp\Zend\library\Zend\Db\Adapter\Abstract.php(860): Zend_Db_Adapter_Pdo_Mysql->_connect()
#2 C:\xampp\Zend\library\Zend\Db\Adapter\Abstract.php(930): Zend_Db_Adapter_Abstract->quote('pass1', NULL)
#3 C:\xampp\Zend\library\Zend\Auth\Adapter\DbTable.php(449): Zend_Db_Adapter_Abstract->quoteInto('`password` = ?', 'pass1')
#4 C:\xampp\Zend\library\Zend\Auth\Adapter\DbTable.php(368): Zend_Auth_Adapter_DbTable->_authenticateCreateSelect()
#5 C:\xampp\Zend\library\Zend\Auth.php(117): Zend_Auth_Adapter_DbTable->authenticate()
#6 C:\xampp\htdocs\Eulen\application\controllers\AuthenticationController.php(27): Zend_Auth->authenticate(Object(Zend_Auth_Adapter_DbTable))
#7 C:\xampp\Zend\library\Zend\Controller\Action.php(516): AuthenticationController->logininAction()
#8 C:\xampp\Zend\library\Zend\Controller\Dispatcher\Standard.php(308): Zend_Controller_Action->dispatch('logininAction')
#9 C:\xampp\Zend\library\Zend\Controller\Front.php(954): Zend_Controller_Dispatcher_Standard->dispatch(Object(Zend_Controller_Request_Http), Object(Zend_Controller_Response_Http))
#10 C:\xampp\Zend\library\Zend\Application\Bootstrap\Bootstrap.php(97): Zend_Controller_Front->dispatch()
#11 C:\xampp\Zend\library\Zend\Application.php(366): Zend_Application_Bootstrap_Bootstrap->run()
#12 C:\xampp\htdocs\Eulen\public\index.php(26): Zend_Application->run()
#13 {main}
Request Parameters:
array (
'controller' => 'authentication',
'action' => 'loginin',
'module' => 'default',
)
我正在尋找一個解決方案,以及一些可能出現的錯誤的人,用我的傳球和用戶(如果我去了拼寫錯誤(我沒有發現任何),不能連接到phpMyAdmin phpmyadmim網站,我可以使用用戶名和密碼輸入)。
我已經嘗試了幾個解決方案,但我無法弄清楚。
我錯過了什麼。
文件的config.ini:
resources.db.params.charset = "utf8"
resources.db.adapter = "pdo_mysql"
resources.db.params.host = localhost
resources.db.params.username = "onetag51_teste"
resources.db.params.password = "*******"
resources.db.params.dbname = "onetag51_eulenhugo"
其更好地把這裏的authenticationcontroller,也許問題是有..
<?php
class AuthenticationController extends Zend_Controller_Action
{
public function init()
{
/* Initialize action controller here */
}
public function indexAction()
{
// action body
}
public function logininAction()
{
// action body
$authAdapter =$this->getAuthAdapter();
$username='hugo';
$password='pass1';
$authAdapter->setIdentity($username)
->setCredential($password);
$auth =Zend_Auth::getInstance();
$result = $auth->authenticate($authAdapter);
if($result->isValid())
{
echo 'valid';
}
else
{
echo 'invalid';
}
}
public function logoutAction()
{
// action body
}
private function getAuthAdapter()
{
$authAdapter = new Zend_Auth_Adapter_DbTable(Zend_Db_Table::getDefaultAdapter());
$authAdapter->setTableName('users')
->setIdentityColumn('username')
->setCredentialColumn('password');
return $authAdapter;
}
}
香港專業教育學院一直在談論我的一個朋友,他告訴我需要設置允許通過zend訪問phpmyadmim的權限...
我該怎麼做?
只是爲了確定,「*******」是您擁有的實際參數config.ini的密碼?或者你只是爲了這個問題而使用它,即使如此,我也會建議將它改爲隨機的。 –
不,我使用我的密碼,但是我切換爲****。 –