如何從SQL查詢結果中返回特定行到底部？

Question

我有一個簡單的SQL查詢，其返回的數據

select [BusinessModel], count(*) As Total from DimHotelExpand 
group by [BusinessModel] 

結果當屬：

DA  53894 
DL  7098 
ECM  1472 
Flex  14789 
GDS  33487 
Lead  1499050 
MT  71306 
Unknown 572467 

我想和值「提前」的行出現在結果的底部。我怎樣才能做到這一點？

Answer 1

你可以試試這個，如果你不知道鉛是否始終最大價值：

select 
    [BusinessModel], count(*) As Total 
from DimHotelExpand 
group by 
    [BusinessModel] 
order by 
    case [BusinessModel] when 'Lead' then 1 else 0 end asc 

Answer 2

你可以通過你的總列順序是（因爲鉛的數量要高）這樣的：

SELECT [BusinessModel], count(*) As Total from DimHotelExpand 
GROUP BY [BusinessModel] 
ORDER BY count(*) 

Answer 3

嘗試這一個 -

SELECT 
     d.BusinessModel 
    , Total = COUNT(1) 
FROM dbo.DimHotelExpand d 
GROUP BY d.BusinessModel 
ORDER BY 
     CASE WHEN d.BusinessModel = 'Lead' THEN 0 ELSE 1 END 
    , Total 

Answer 4

您可以嘗試使用「union all」。

select [BusinessModel], count(*) As Total from DimHotelExpand 
where [BusinessModel] <> 'Lead' 
group by [BusinessModel] 
union all 
select [BusinessModel], count(*) As Total from DimHotelExpand 
where [BusinessModel] = 'Lead' 
group by [BusinessModel] 

「Order by」的解決方案，我相信不能正常工作。只有在「領先」是更大的商業模式時才能正常工作。

我認爲frikozoid解決方案也是有效的。