如何從句子中移除單詞的數組？

我有停止詞的數組：如何從句子中移除單詞的數組？

myArray = ["","a","ago","also","am","an","and","ani","ar","aren't","arent","as","ask","at","did","didn't","didnt","do","doe","would","be","been","best","better"]

我想從一個句子中刪除匹配的項目：

str = 'A something and hello'

所以就變成：

'something hello'

1.我怎樣才能做到這一點在紅寶石？

2.我怎樣才能做到這一點的字符數組（刪除所有匹配的字符）？

這裏的字符數組：

["(",")","@","#","^"]

來源

2011-11-16 user1049097

你想在第二種情況下輸出什麼？ – Tilo

sentence = 'A something and hello' 
array = ["","a","ago","also","am","an","and","ani","ar","aren't","arent", 
      "as","ask","at","did","didn't","didnt","do","doe","would", 
      "be","been","best","better"] 


sentence.split.delete_if{|x| array.include?(x)}.join(' ') 

=> "A something hello"

你可能想比較之前downcase所有的話，擺脫在句子開頭的「A」的：

sentence.split.delete_if{|x| array.include?(x.downcase)}.join(' ') 

=> "something hello"

如果你有一個字符串數組，更容易：

(sentence.split - array).join(' ') 
=> "A something hello" # but note that this doesn't catch the "A"

也刪除特殊字符：

special = ["(",")","@","#","^"] 

sentence.split.delete_if{|x| array.include?(x.downcase) || special.include?(x) }.join(' ')

另一種方法來刪除單詞或短語是：

array.each do |phrase| 
    sentence.gsub!(/#{phrase}/,'') 
end

來源

2011-11-16 06:56:45 Tilo

謝謝！有沒有類似的方式來做一個字符數組呢？（刪除任何匹配的字符） – user1049097

@Tilo如果我不想刪除像「謝謝」這樣的詞並且我已經排在[[「thank you」，.....] –

我如何添加示例這樣做 - 看到我的回答 – Tilo

-1

array.map {|s| s.gsub(keyword, '')}

來源

2011-11-16 06:55:41

你應該在你的答案周圍放置一些描述性文字來解釋它在做什麼。 – Spence

我的解決辦法：

stop_words = ["","a","ago","also","am","an","and","ani","ar","aren't","arent","as","ask","at","did","didn't","didnt","do","doe","would","be","been","best","better"] 
output = %w(A something and hello) - stop_words

來源

2011-11-16 07:02:51 Virtual

結束很好，但輸入應該是一個字符串 – 2011-11-16 07:05:57

also..output應該是另一個字符串，而不是一個數組 – rubyprince

一個單Tilo的答案的變體是乾淨的和不區分大小寫的（儘管它是重要的）變成全部小寫輸出，這可能不是所有用途的理想選擇）：

(sentence.downcase.split - array).join(' ')

來源

2015-06-09 15:49:13 ecormany

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