獲取在線文件的內容並將其分配給變量

Question

如何檢索文件的內容並將其分配給字符串？

該文件位於https服務器上，內容爲純文本。

Answer 1

最佳答案我找到了：

public static String readPage(String url, String delimeter) 
{ 
    try 
    { 
     URL URL = new URL(url); 
     URLConnection connection = URL.openConnection(); 
     BufferedReader reader = new BufferedReader(new InputStreamReader(connection.getInputStream())); 
     String line, lines = ""; 
     while ((line = reader.readLine()) != null) 
     { 
      if(lines != "") 
      { 
       lines += delimeter; 
      } 
      lines += line; 
     } 
     return lines; 
    } 
    catch (Exception e) 
    { 
     return null; 
    } 
} 

Answer 2

查看Java API中的URL Class。

很確定你需要的只是在那裏。

Answer 3

首先使用URL類的java從服務器下載文件。

String url = "http://url"; 
java.io.BufferedInputStream in = new java.io.BufferedInputStream(new 
java.net.URL(url).openStream()); 
java.io.FileOutputStream fos = new java.io.FileOutputStream("file.txt"); 
java.io.BufferedOutputStream bout = new BufferedOutputStream(fos,1024); 
byte data[] = new byte[1024]; 
while(in.read(data,0,1024)>=0) 
{ 
    bout.write(data); 
} 
bout.close(); 
in.close(); 

然後閱讀使用FileInputStream級Java

File file = new File("file.txt"); 
int ch; 
StringBuffer strContent = new StringBuffer(""); 
FileInputStream fin = null; 
try { 
fin = new FileInputStream(file); 
while ((ch = fin.read()) != -1) 
strContent.append((char) ch); 
fin.close(); 
} catch (Exception e) { 
System.out.println(e); 
} 
System.out.println(strContent.toString()); 

Answer 4

的下載的文件，我建議Apache HttpClient：簡單，乾淨的代碼，它處理由服務器發送的字符編碼 - 這java.net.URL/java.net.URLConnection力你自己處理：

String url = "http://example.com/file.txt"; 

HttpClient client = new DefaultHttpClient(); 
HttpResponse response = client.execute(new HttpGet(url)); 
String contents = EntityUtils.toString(response.getEntity());