C++ if循環和函數

Question

在我的程序中，它首先要求僱員的數量。 if循環說，如果輸入是輸入< 1輸出說「請輸入一個值至少1」。如果輸入0或-1，則輸出供用戶糾正，但只能執行一次。所以如果用戶輸入-1兩次，它將會第二次運行。它也用第二個if循環來做到這一點。

#include <iomanip> 
#include <iostream> 

using namespace std; 

int getNumEmployees(); 
int getDaysMissed(int); 
double getAverageDays(int,int); 

int main() 
{ 
    int numEmployees; 
    int daysMissed; 
    double average; 

    //Get the number of employees 
    numEmployees = getNumEmployees(); 

    //Get the number of days missed 
    daysMissed = getDaysMissed(numEmployees); 

    //Get the average days missed 
    average = getAverageDays(numEmployees, daysMissed); 

    cout << "The average number of days missed is: " << average << endl; 

    system("pause"); 
    return 0; 
} 

int getNumEmployees() 
{ 
    int employeeNum; 

    cout << "Enter the number of company employees: "; 
    cin >> employeeNum; 

    if(employeeNum < 1) 
    { 
     cout << "Please enter a value greater than 0 " << endl; 
     cin >> employeeNum; 
    } 

    return employeeNum; 
} 


int getDaysMissed(int employeeNum) 
{ 
    int totalDays = 0; 
    int employee; 

    for(int count = 1; count <= employeeNum; count++) 
    { 
     cout << "Enter the number of days employee " << count << " missed: "; 
     cin >> employee; 
     if(employee < 0) 
     { 
      cout << "Enter a positive number for days missed " <<  endl; 
      cin >> employee; 
     } 

     totalDays += employee; 
    } 
    return totalDays; 
} 

double getAverageDays(int employeeNum, int totalDays) 
{ 
    double averageDays; 
    averageDays = totalDays/employeeNum; 
    return averageDays; 
} 

Answer 1

更改此：

if(employeeNum < 1) 

這樣：

while(employeeNum < 1) 

你想要循環。正如chris提到的，if不會循環。