失敗/錯誤：預計（$ stdout）.to接收（：puts）。

Question

構建新客戶在進入熟食店時將使用的方法。 take_a_number方法應該接受兩個參數，即當前行的數組（katz_deli）和包含想要加入行的人的名稱的字符串。該方法應該返回該人的姓名以及他們的位置。我該如何安排，以便當前行的數組等於names數組的數量？

katz_deli = [] 
 

 
def line(array) 
 
    if array[0] == nil 
 
    puts "The line is currently empty." 
 
end 
 
end 
 

 
def take_a_number(array, name) 
 
    i=0 
 
    counter = 1 
 
    while array.count != name.length 
 
    array[i] = counter 
 
    i+=1 
 
    counter +=1 
 
    end 
 
    if array.count > 1 
 
    puts "The line is currently:" 
 
    end 
 
    name.each_with_index {|val, index| puts "#{index+1}. #{val}"} 
 
    end

這裏是Rspec的文件：

describe 'Deli Counter' do 
 

 
    let(:katz_deli) { [] } 
 
    let(:other_deli) { ["Logan", "Avi", "Spencer"] } 
 

 
    describe "#line" do 
 
    context "there is nobody in line" do 
 
     it "should say the line is empty" do 
 
     # This line checks the current standard output (your terminal screen) 
 
     # to make sure the correct output has been puts'ed. 
 
     expect($stdout).to receive(:puts).with("The line is currently empty.") 
 
     line(katz_deli) 
 
     end 
 
    end 
 

 
    context "there are people in line" do 
 
     it "should display the current line" do 
 
     expect($stdout).to receive(:puts).with("The line is currently: 1. Logan 2. Avi 3. Spencer") 
 
     line(other_deli) 
 
     end 
 
    end 
 
    end

Answer 1

我工作的時間提前了錯誤的方法

katz_deli = [] 
 

 
def line(array) 
 
    if array.count > 1 
 
    output = "The line is currently:" 
 
    array.each_with_index {|val, index| output << " #{index+1}. #{val}"} 
 
    puts output 
 
    else 
 
    puts "The line is currently empty." 
 
end 
 
end