2017-05-29 65 views
0

我正在嘗試學習flask_sqlalchemy中的關係,但確實很難獲得代碼的工作。首先,在這個主題上缺乏很好的教程,但我仍然加入了一些信息來編寫代碼,但是我沒有得到預期的結果。瞭解flask_sqlalchemy中的一對多關係

你能解釋我在這段代碼中做錯了什麼嗎?

from flask import Flask 
from flask_sqlalchemy import SQLAlchemy 

app = Flask(__name__) 
app.config['SQLALCHEMY_DATABASE_URI'] = 'postgres://<my_user>:<my_password>@localhost/flask_apps' 
db = SQLAlchemy(app) 


class Universe(db.Model): 
    __tablename__ = 'universe' 
    id = db.Column(db.Integer, primary_key=True) 
    name = db.Column(db.String(30)) 
    hero = db.relationship('Characters', backref='u_name', lazy='dynamic') 


class Characters(db.Model): 
    __tablename__= 'characters' 
    id = db.Column(db.Integer, primary_key=True) 
    name = db.Column(db.String(50)) 
    uni = db.Column(db.Integer, db.ForeignKey('universe.id')) 

if __name__ == '__main__': 
    db.drop_all() 
    db.create_all() 
    dc = Universe(name='DC') 
    marvel = Universe(name='Marvel') 
    db.session.add(dc) 
    db.session.add(marvel) 
    db.session.commit() 
    flash = Characters(name='Flash', u_name=dc) 
    batman = Characters(name='Batman', u_name=dc) 
    arrow = Characters(name='Arrow', u_name=dc) 
    ironman = Characters(name='IronMan', u_name=marvel) 
    thor = Characters(name='Thor', u_name=marvel) 
    db.session.add(flash) 
    db.session.add(ironman) 
    db.session.commit() 

    u = Universe.query.filter_by(name='DC').first() 
    print(u.hero) 

這是我得到的輸出。

SELECT characters.id AS characters_id, characters.name AS characters_name, characters.uni AS characters_uni 
FROM characters 
WHERE %(param_1)s = characters.uni 

Process finished with exit code 0 

我期待得到屬於特定宇宙的角色名稱。不太確定我在這裏錯過了什麼。

回答

0

我能夠解決這個問題,這個問題是hero作爲一個單一的價值屬性,而不是一個集合曲解。所以使用下面的查詢工作。

u = Universe.query.filter_by(name='DC').first() 
    for item in u.hero[:]: 
     print(item.name)