用的preg_match

Question

捕獲標籤我用這個功能來讀取和顯示信息，我想從RSS VIMEO：

$url=array('http://vimeo.com/channels/hdnature/videos/rss'); 



foreach($url as $value){ 
$homepage = file_get_contents($value); 
$movies = new SimpleXMLElement($homepage); 
     foreach($movies->channel->item as $opt){ 


    $title= $opt->title; 
    $tittle=mysql_real_escape_string($title); 

    $link=$opt->link; 
    $links=mysql_real_escape_string($link); 


    $des=$opt->description; 
    $dess=mysql_real_escape_string($des); 
    //Use that namespace 
    $namespaces = $opt->getNameSpaces(true); 
    //Now we don't have the URL hard-coded 
    $dc = $opt->children($namespaces['dc']); 
    //echo $dc->publisher; 
    //echo $dc->creator; 
    //echo $link; 


    $imgpattern = '/href="(.*?)"/i'; 
    preg_match($imgpattern, $des, $matches); 
    $imageurl['image'] = $matches[1]; 
    echo $imageurl['image']; 

    $tag = '/">(.*?)<\/a>/'; 
    preg_match($tag, $des, $matches); 
    $tagurl['name'] = $matches[1]; 
    echo $tagurl['name']; 

我有<description></description>領域內的標籤這個名單：

<p><strong>Tags:</strong> 
<a href="http://vimeo.com/tag:art">Art</a>, 
<a href="http://vimeo.com/tag:film">Film</a>, 
<a href="http://vimeo.com/tag:movie">Movie</a>, 
<a href="http://vimeo.com/tag:cinema">Cinema</a>, 
<a href="http://vimeo.com/tag:creation">Creation</a>, 
<a href="http://vimeo.com/tag:concept">Concept</a>, 
<a href="http://vimeo.com/tag:experimental">Experimental</a>, 
<a href="http://vimeo.com/tag:sound">Sound</a>, 
<a href="http://vimeo.com/tag:music">Music</a>, 
<a href="http://vimeo.com/tag:motion">Motion</a>, 
<a href="http://vimeo.com/tag:copyleft">Copyleft</a> 
and 
<a href="http://vimeo.com/tag:videoart">Videoart</a> 
</p> 

我搜到保存在我的數據庫中只有像藝術，電影，電影等字。

我需要用方括號保存列表，我嘗試使用preg_match。

我有這樣的功能：

$tag = '/</strong>(.*?)</a></p>/'; 
preg_match($tag, $des, $matches); 
$taglist['name'] = $matches[1]; 
echo $taglist['name']; 

但我只收到一個錯誤，而不是結果，我希望的。

Answer 1

試試這個