的Oracle SQL發現使用探測法

Question

相似字符串我有表HumanNames

輸入是

|HumanName  | 
|------------- | 
|Kamil   | 
|Azer   | 
|John   | 
|Elmir   | 
|Kamal   | 
|Elmar   | 
|Orxan   | 
|Elnar   | 

我需要寫的查詢，這將給像另一名結果名。 所需的輸出是

|NamesWhichLikes | 
|------------- | 
|Kamil,Kamal  | 
|Elmir,Elmar,Elnar| 
|     | 

Answer 1

上名字的soundex試試這個使用listagg和group by：

with your_table (HumanName) as (
select 'Kamil' from dual union all 
select 'Azer' from dual union all 
select 'John' from dual union all 
select 'Elmir' from dual union all 
select 'Kamal' from dual union all 
select 'Elmar' from dual union all 
select 'Orxan' from dual union all 
select 'Elnar' from dual 
) 
------ Test data setup ends here ------ 


select 
    listagg(humanname,',') within group (order by humanname) nameswhichlikes 
from your_table 
group by soundex(humanname) 
having count(*) > 1; 

產地：

+---------------------------+ 
| NAMESWHICHLIKES   | 
+---------------------------+ 
| Elmar,Elmir,Elnar   | 
+---------------------------+ 
| Kamal,Kamil    | 
+---------------------------+ 

重名的情況：

select 
    listagg(humanname,',') within group (order by humanname) nameswhichlikes 
from (select distinct humanname from your_table) 
group by soundex(humanname) 
having count(*) > 1;