Java的MySQL的：ClassNotFoundException的 - >找不到驅動程序

可能重複：
ClassNotFoundException com.mysql.jdbc.Driver Java的MySQL的：ClassNotFoundException的 - >找不到驅動程序

我已經包括mysql-connector-java-5.1.16-bin.jar到我的Eclipse庫，這個代碼是基於我有教程因爲我之前沒有在Java中使用過MySQL，所以在網上找到它。不幸的是我沒有看到，我使用acutual mysql-connector-java-5.1.16-bin.jar和控制檯打印Could not find driver.意味着ClassNotFoundException被拋出。你有沒有看到我看不到的（可能是顯而易見的）問題？

import java.sql.Connection; 
import java.sql.DriverManager; 
import java.sql.ResultSet; 
import java.sql.SQLException; 
import java.sql.Statement; 
import java.util.Date; 
import java.util.HashMap; 
import java.util.Map; 
import java.sql.Timestamp; 

public class MysqlConnector { 

    private static MysqlConnector instance = null; 
    private static Connection conn = null; 

    private static String dbHost = "localhost"; 
    private static String dbPort = "3306"; 
    private static String database = "sample"; 
    private static String dbUser = "root"; 
    private static String dbPassword = ""; 

    public MysqlConnector() { 
     try { 
      Class.forName("com.mysql.jdbc.Driver"); 
      conn = DriverManager.getConnection("jdbc:mysql://" + dbHost + ":" 
        + dbPort + "/" + database + "?" + "user=" + dbUser + "&" 
        + "password=" + dbPassword); 
     } catch (ClassNotFoundException e) { 
      System.out.println("Could not find driver."); //TODO LOGGER 
     } catch (SQLException e) { 
      System.out.println("Could not connect to database."); //TODO LOGGER 
     } 
    } 

    public static MysqlConnector getInstance() 
    { 
     if(instance == null) 
      instance = new MysqlConnector(); 
     return instance; 
    } 

    public boolean validateApiKey(String apikey) 
    { 
     if(conn != null) 
     { 
      Statement query; 
      try { 
       query = conn.createStatement(); 

       String sql = "SELECT startdate, expiration, active " + "FROM apikeys " 
         + "WHERE apikey = '" + apikey +"'"; 
       ResultSet result = query.executeQuery(sql); 

       if(result.getFetchSize()>0 && result.getInt("active")==1){ 
        Date now = new Date(); 
        Date startdate = result.getDate("startdate"); 
        Date expirationdate = result.getDate("expiration"); 
        if(now.before(expirationdate) && now.after(startdate)){ 
         return true; 
        } else { 
         return false; 
        } 
       } else { 
        return true; 
       } 
      } catch (SQLException e) { 
       e.printStackTrace(); 
       return false; 
      } 
     } 
     return false; 
    } 

}

來源

2011-06-01 Jack Murphy

這是一個幾乎可以肯定的類路徑問題。看看非常相似票 – 2011-06-01 15:42:31

可能重複的是不是蝕。所以它不是一個確切的副本。 – Bozho 2011-06-01 15:43:56

我不確定是否同意這是一個確切的副本，至少在這裏我找到了一個我無法在其他票證中找到的答案。 – 2011-06-01 16:01:55