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我想用Laravel一對一的關係來實現這個查詢。Laravel 4.2一對一關係返回NULL
SELECT `path_filepath` from path where `path_id` = (SELECT `path_id` from file where file_id = 1)
我想Filedb::find(1)->path()->path_filepath
。但path()
總是返回NULL。
[database]
table: file
file_id
file_name
path_id
table: path
path_id
path_filepath
型號
class Filedb extends Eloquent {
public $timestamps = false;
protected $table = 'file';
protected $primaryKey = 'file_id';
protected $connection = 'dl_database';
public function path(){
return $this->hasOne('Filepath','path_id','path_id');
}
}
class Filepath extends Eloquent {
public $timestamps = false;
protected $table = 'path';
protected $primaryKey = 'path_id';
protected $connection = 'dl_database';
public function filedb()
{
return $this->belongsTo('Filedb', 'path_id');
}
}
我的控制器
var_dump(Filedb::find(1)->path());
echo '<br>';
$queries = DB::connection('dl_database')->getQueryLog();
$last_query = end($queries);
var_dump($queries);
Outout
NULL
array(1) { [0]=> array(3) { ["query"]=> string(61) "select * from `file` where `file`.`file_id` = ? limit 1" ["bindings"]=> array(1) { [0]=> int(1) } ["time"]=> float(0.85) } }
由於工作,但你路徑功能缺失的回報。 – dragon1993 2014-09-30 19:55:42
@ dragon1993很好,是的,就像你的一樣。我從你的代碼複製粘貼它;) – 2014-09-30 21:53:21