SQL oracle where clause

Question

SELECT * 
FROM PERSONNE 
WHERE PERSONNE.NO_PERSONNE = GENEALOGIE.NO_PERSONNE 
    AND GENEALOGIE.TYPE_EVENEMENT_GEN = 'Baptême' 
    AND GENEALOGIE.LIEU_EVENEMENT_GEN != 'Ste-Lubie' 
    AND GENEALOGIE.TYPE_EVENEMENT_GEN = 'Mariage' 
    AND GENEALOGIE.LIEU_EVENEMENT_GEN = 'Ste-Lubie'; 

我很想做那樣的事情。

選擇Ste-Lubie的人在哪裏結婚，但不是Ste-Lubie的「Baptême」。

Answer 1

請嘗試此解決方案：

SELECT * 
FROM PERSONNE 
    JOIN GENEALOGIE ON PERSONNE.NO_PERSONNE = GENEALOGIE.NO_PERSONNE 
    LEFT JOIN GENEALOGIE GEN_NOT ON (PERSONNE.NO_PERSONNE = GENEALOGIE.NO_PERSONNE AND GENEALOGIE.TYPE_EVENEMENT_GEN = 'Baptême' AND GENEALOGIE.LIEU_EVENEMENT_GEN = 'Ste-Lubie') 
WHERE 
    GENEALOGIE.TYPE_EVENEMENT_GEN = 'Mariage' 
    AND GENEALOGIE.LIEU_EVENEMENT_GEN = 'Ste-Lubie' 
    AND GEN_NOT.NO_PERSONNE IS NULL 

了一些修改，要工作，我猜...

Answer 2

嘗試......

SELECT T1.*,T2.* 
FROM PERSONNE T1 
INNER JOIN GENEALOGIE T2 
ON T1.NO_PERSONNE = T2.NO_PERSONNE 
WHERE T2.TYPE_EVENEMENT_GEN = 'Baptême' 
AND T2.LIEU_EVENEMENT_GEN != 'Ste-Lubie' 
AND T2.TYPE_EVENEMENT_GEN = 'Mariage' 
AND T2.LIEU_EVENEMENT_GEN = 'Ste-Lubie'; 

Answer 3

SELECT P.* 
FROM PERSONNE P,GENEALOGIE G 
WHERE P.NO_PERSONNE = G.NO_PERSONNE 
    AND G.TYPE_EVENEMENT_GEN = 'Mariage' 
    AND G.LIEU_EVENEMENT_GEN = 'Ste-Lubie' 
    AND NOT EXISTS 
    (SELECT 'X' FROM GENEALOGIE G1 
    WHERE P.NO_PERSONNE = G1.NO_PERSONNE 
     AND G1.TYPE_EVENEMENT_GEN = 'Baptême' 
     AND G1.LIEU_EVENEMENT_GEN = 'Ste-Lubie') 

OR

SELECT P.* 
FROM PERSONNE P 
WHERE P.NO_PERSONNE IN 
    (SELECT NO_PERSONNE FROM GENEALOGIE G1 
    WHERE G1.TYPE_EVENEMENT_GEN = 'Mariage' 
     AND G1.LIEU_EVENEMENT_GEN = 'Ste-Lubie' 
    MINUS 
    SELECT NO_PERSONNE FROM GENEALOGIE G1 
    WHERE G1.TYPE_EVENEMENT_GEN = 'Baptême' 
     AND G1.LIEU_EVENEMENT_GEN = 'Ste-Lubie')