HTML按鈕的onclick功能不使用jQuery可變工作作爲參數

Question

success: function(jsonresponse) { 
    data = JSON.stringify(jsonresponse); 

    $.each(JSON.parse(data), function (index, item) { 
    var Id=item.id; 
    var JobId=item.JobId; 

var eachrow = "<tr>" 
      + "<td>" + item.id + "</td>" 
      + "<td>" + item.JobId + "</td>" 
      + "<td>" + item.UserId + "</td>" 
      + "<td>" + item.updatedAt + "</td>" 
      + "<td>" + "<button onclick='myFunction(JobId,Id, \"accepted\")' class='btn btn-success btn-block'>Reject</button>" + "</td>" 
      + "<td>" + "<button onclick='myFunction(JobId,Id, \"rejected\")' class='btn btn-success btn-block'>Reject</button>" + "</td>" 
      + "</tr>"; 

$('#tbody2').append(eachrow); 
}); 

}, 

myFuntion（的JobId，ID，\「接受\」）不與變量可以作爲參數，但手動添加時則函數的工作，如myFuntion（1， 3，\ 「接受\」）。

Answer 1

問題：你是不是在串聯的HTML代碼的JobId & Id？

解決方案： 正確串接您JobId & Id變量在HTML代碼中，你將有利於爲走：

success: function(jsonresponse) { 
    data = JSON.stringify(jsonresponse); 

    $.each(JSON.parse(data), function (index, item) { 
    var Id=item.id; 
    var JobId=item.JobId; 

var eachrow = "<tr>" 
      + "<td>" + item.id + "</td>" 
      + "<td>" + item.JobId + "</td>" 
      + "<td>" + item.UserId + "</td>" 
      + "<td>" + item.updatedAt + "</td>" 
      + "<td>" + "<button onclick='myFunction("+JobId+","+Id+", \"accepted\")' class='btn btn-success btn-block'>Reject</button>" + "</td>" 
      + "<td>" + "<button onclick='myFunction("+JobId+","+Id+", \"rejected\")' class='btn btn-success btn-block'>Reject</button>" + "</td>" 
      + "</tr>"; 

$('#tbody2').append(eachrow); 
}); 

},