的Sybase SQL + PHP，爲什麼附近有語法錯誤 '='

Question

//$type has value of "Hello+World" 
$type = $_POST['series']; 

$sql = "select max(id) from TABLE_NAME where type = " . $type; 

$result = sybase_query ($sql, $db_ro_conn) or die(db_error("query failed $sql")); 
$row = sybase_fetch_row($result) 

我得到錯誤「不正確的語法不久 「=」，Y15，在$ SQL行過程N/A。

可能是什麼？原因發生這種情況不知怎的，這是行不通的希望得到任何幫助，感謝你周圍的$ type

Answer 1

把雙引號是這樣的：！

$type = $_POST['series']; 

$sql = "select max(id) from TABLE_NAME where type = '" . $type. "'"; 

$result = sybase_query ($sql, $db_ro_conn) or die(db_error("query failed $sql")); 
$row = sybase_fetch_row($result) 

Answer 2

讓我開始與這個總是逃避POST /在您的查詢中獲取值！

錯誤可能是由$ type是字符串而不是引用引起的。嘗試改變$ SQL來

$sql = "select max(id) from TABLE_NAME where type = '" . $type."'"; 

Answer 3

你是不是引用值：

$type = str_replace("'", "''", $_POST['series']); 
$sql = "select max(id) from TABLE_NAME where type = '" . $type . "'";