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我在Windows Phone 8.1應用程序中使用RestSharp。當服務器返回代碼不是200的響應時,RestClient拋出異常。Wiki說我應該得到正確的狀態碼。我想獲得響應的內容,因爲服務器返回錯誤消息。服務器響應的RestSharp - 如何處理非200響應? RestClient在執行時拋出異常
private async Task<T> ExecuteAsync<T>(IRestRequest request)
{
if (!_networkAvailableService.IsNetworkAvailable)
{
throw new NoInternetException();
}
request.AddHeader("Accept", "application/json");
IRestResponse<T> response;
try
{
response = await _client.Execute<T>(request); //here I get exception
}
catch (Exception ex)
{
throw new ApiException();
}
HandleApiException(response);
return response.Data;
}
private void HandleApiException(IRestResponse response)
{
if (response.StatusCode == HttpStatusCode.OK)
{
return;
}
//never reach here :(
ApiException apiException;
try
{
var apiError = _deserializer.Deserialize<ApiErrorResponse>(response);
apiException = new ApiException(apiError);
}
catch (Exception)
{
throw new ApiException();
}
throw apiException;
}
樣本:
HTTP/1.1 400 Bad Request
Cache-Control: no-cache
Pragma: no-cache
Content-Length: 86
Content-Type: application/json;charset=UTF-8
Expires: -1
Server: Microsoft-IIS/8.0
Access-Control-Allow-Origin: *
X-Powered-By: ASP.NET
Date: Mon, 28 Sep 2015 12:30:10 GMT
Connection: close
{"error":"invalid_token","error_description":"The user name or password is incorrect"}
的確如此。使用普通的RestSharp這不會發生。在使用RestSharp Portable時,您需要按照上文所述配置您的客戶端!對於Xamarin使用的PCL組件,這必須完成。 – John