SQL - 與案例不同時

Question

當我使用以下查詢時，它會返回重複的外部ID，因爲它會將不同的案例列爲不同的行。

SELECT DISTINCT 

    OENT.OTHER_EXTERNAL_ID                          AS 'Agent Master Number'  
    ,CASE WHEN SE.Organization_Name IS NULL OR RTRIM(LTRIM(SE.ORGANIZATION_NAME)) = '' THEN '' ELSE SE.ORGANIZATION_NAME END  AS 'Agent' 

    GROUP BY 

    OENT.OTHER_EXTERNAL_ID                        
    ,CASE WHEN SE.Organization_Name IS NULL OR RTRIM(LTRIM(SE.ORGANIZATION_NAME)) = '' THEN '' ELSE SE.ORGANIZATION_NAME END 

我在哪裏可以正確使用不同的名稱，因此無論它滿足何種情況，它都會將行列出一行。

感謝

問題是，它的回頭率

AGENT_NUMBER AGENT 

MA12348677 DREHWING, DOUGLAS 

MA12348677 DREHWING, DOUGLAS A 

，我想這是一個行，因爲它們具有相同的AGENT_NUMBER

Answer 1

select distinct 
OENT.OTHER_EXTERNAL_ID AS AGENT_NUMBER, 
CASE 
    WHEN SE.Organization_Name IS NULL OR RTRIM(LTRIM(SE.ORGANIZATION_NAME)) = '' THEN '' 
    ELSE upper(SE.ORGANIZATION_NAME) 
END AS AGENT 
FROM SomeTableName 
order by AGENT_NUMBER 

它仍然會在情況下返回副本如果代理號碼不同。如果你想找到重複的名字然後

select AGENT, count (AGENT_NUMBER) from (
    select OENT.OTHER_EXTERNAL_ID AS AGENT_NUMBER, 
    CASE 
     WHEN SE.Organization_Name IS NULL OR RTRIM(LTRIM(SE.ORGANIZATION_NAME)) = '' THEN '' 
     ELSE upper(SE.ORGANIZATION_NAME) 
    END AS AGENT 
    FROM SomeTableName 
    ) 
    group by AGENT 
    HAVING count (AGENT_NUMBER) >1 
    order by AGENT 

要找到相同的代理號重名：

select AGENT_NUMBER, count (AGENT) from (
    select OENT.OTHER_EXTERNAL_ID AS AGENT_NUMBER, 
    CASE 
     WHEN SE.Organization_Name IS NULL OR RTRIM(LTRIM(SE.ORGANIZATION_NAME)) = '' THEN '' 
     ELSE upper(SE.ORGANIZATION_NAME) 
    END AS AGENT 
    FROM SomeTableName 
    ) 
    group by AGENT_NUMBER 
    HAVING count (AGENT) >1 
    order by AGENT_NUMBER