POSTGRESQL：創建表作爲選擇特定類型的列

Question

我有一個混合類型的數據表（真正的，integrer，字符...）但我只會恢復具有實際值的列。

我可以構建這樣的：

SELECT 'SELECT ' || array_to_string(ARRAY(
select 'o' || '.' || c.column_name 
from information_schema.columns as c 
where table_name = 'final_datas' 
and c.data_type = 'real'), ',') || ' FROM final_datas as o' As sqlstmt 

給出的是：

"SELECT o.random,o.struct2d_pred2_num,o.pfam_num,o.transmb_num [...] FROM final_datas as o" 

的我想創建一個表，這些列。當然，這樣做，不起作用：

create table table2 as (
SELECT 'SELECT ' || array_to_string(ARRAY(
select 'o' || '.' || c.column_name 
from information_schema.columns as c 
where table_name = 'final_datas' 
and c.data_type = 'real'), ',') || ' FROM final_datas as o' As sqlstmt 
) 

建議？

Answer 1

你需要生成整個CREATE TABLE語句動態SQL：

SELECT 'CREATE TABLE table2 AS SELECT ' || array_to_string(ARRAY(
select 'o' || '.' || c.column_name 
from information_schema.columns as c 
where table_name = 'final_datas' 
and c.data_type = 'real'), ',') || ' FROM final_datas as o' As sqlstmt 

結果可以EXECUTE sqlstmt;