我很困惑,爲什麼這是OT工作:JS使用變量作爲document.getElementById的ID不起作用?
var blocks = document.getElementsByTagName("td");
var i = 0;
for(i=0;i<blocks.length;i++){
var id = String(blocks[i].id);
var col_pos_y = document.getElementById(id).style.top;
alert(col_pos_y);
}
我失去了一些東西,因爲Firefox的似乎只是警告了一個空白的警告信息?任何人都知道爲什麼這不起作用?
這是產生的HTML/PHP代碼TD的
<table cellspacing="0" cellpadding="0" style="position: absolute; top: 80%; z-index:5;" border="0">
<?php
$blocks = array();
for($k=1;$k<=3;$k++){
$row_number = "row_".$k;
?>
<tr id="<?php echo $row_number; ?>">
<?
for($i=0;$i<=100;$i++){
if($k==1){
$rand_number = rand(0, 100);
}
else if($k==2){
$rand_number = rand(30, 100);
}
else if($k==3){
$rand_number = rand(50, 100);
}
if($rand_number<50){
for($l=0;$l<=count($blocks);$l++){
$row_counter = $k-1;
if($blocks[$l]=="row_".$row_counter."_col_".$i."_type_grass"){
$block_exists="true";
break;
}
else{
$block_exists="false";
}
}
if($block_exists=="true"){
array_push($blocks, $row_number."_col_".$i."_type_grass");
$background_position = generate_dirt_block();
?>
<td id="<?php echo $row_number; ?>_col_<?php echo $i ?>_type_grass" style="font-size: 10px; cursor: pointer; background-image:url('img/terrain.png'); background-repeat: no-repeat; background-position: <?php echo $background_position ?>; min-width: 32px; height: 32px;">
</td>
<?php
}
else{
array_push($blocks, $row_number."_col_".$i."_type_blank");
?>
<td id="<?php echo $row_number; ?>_col_<?php echo $i ?>_type_blank" style="font-size: 10px; min-width: 32px; height: 32px;">
</td>
<?php
}
}
else if($rand_number>=50 && $rand_number<=100){
array_push($blocks, $row_number."_col_".$i."_type_grass");
for($l=0;$l<=count($blocks);$l++){
$row_counter = $k-1;
if($blocks[$l]=="row_".$row_counter."_col_".$i."_type_grass"){
$block_exists="true";
break;
}
else{
$block_exists="false";
}
}
if($block_exists=="true"){
$background_position = generate_dirt_block();
?>
<td id="<?php echo $row_number ?>_col_<?php echo $i ?>_type_grass" style="font-size: 10px; cursor: pointer; background-image:url('img/terrain.png'); background-repeat: no-repeat; background-position: <?php echo $background_position ?>; min-width: 32px; height: 32px;">
</td>
<?php
}
else{
?>
<td id="<?php echo $row_number; ?>_col_<?php echo $i ?>_type_grass" style="font-size: 10px; cursor: pointer; background-image:url('img/terrain.png'); background-repeat: no-repeat; background-position: 0px -32px; min-width: 32px; height: 32px;">
<div style="width: 100%; position: relative; top: 0px;">
<div style="background-image:url('img/terrain.png'); background-repeat: no-repeat; background-position: -384px 0px; width: 32px; height: 10px; position: absolute; top: -17px;">
</div>
</div>
</td>
<?php
}
}
}
?>
</tr>
<?php
}
?>
</table>
你能發佈與此相關的HTML嗎?阿洛斯,你爲什麼在分裂後改絃樂?它似乎是將字符串重新組合起來,就像調用split()之前一樣。 – phatskat 2012-02-22 15:17:47
「block_id」是否有值?你的TD ID是什麼樣的? – 2012-02-22 15:18:09
你忽略了,那是我試着繞過它,但是'document.getElementById(blocks [i] .id).style.top;'由於某種奇怪的原因不起作用。我真的不能發佈整個HTML代碼,因爲它是生成這些td的php,它像100行代碼,但我會嘗試 – 2012-02-22 15:20:33