2
A
回答
0
我問我的朋友(主美香)關於這一點,並給了我這個答案,它的工作原理正好。這裏的答案與列名略有不同。
SELECT
PVTIN.EMPNO, PVTIN.DTRDATE, PVTIN.TIMEIN, PVTOUT.[TIMEOUT], PVTIN.[AM OUT], PVTOUT.[AM IN], PVTIN.[LUNCH OUT], PVTOUT.[LUNCH IN], PVTIN.[PM OUT], PVTOUT.[PM IN]
FROM
(SELECT EMPNO, DTRDATE, [SHIFT] AS TIMEIN, AMBREAK AS [AM OUT], [LUNCH] AS [LUNCH OUT], [PMBREAK] AS [PM OUT] FROM
(select * from
(Select EMPNO, CONVERT(DATE, DTRDATE) AS DTRDATE, TRANS_TYPE, DT_START from dtr_emp_trans) TIN
PIVOT
(MAX(DT_START) FOR TRANS_TYPE IN ([SHIFT],[AMBREAK],[LUNCH],[PMBREAK])) PVT) PVTIN) PVTIN
LEFT JOIN
(SELECT EMPNO, DTRDATE, [SHIFT] AS TIMEOUT, AMBREAK AS [AM IN], [LUNCH] AS [LUNCH IN], [PMBREAK] AS [PM IN] FROM
(select * from
(Select EMPNO, CONVERT(DATE, DTRDATE) AS DTRDATE, TRANS_TYPE, DT_END from dtr_emp_trans) TIN
PIVOT
(MAX(DT_END) FOR TRANS_TYPE IN ([SHIFT],[AMBREAK],[LUNCH],[PMBREAK])) PVT) PVTOUT) PVTOUT
ON PVTIN.EMPNO = PVTOUT.EMPNO AND PVTIN.DTRDATE = PVTOUT.DTRDATE
是的。我就是這樣。
0
自加入也可能有用。現在沒有SQL Server。查詢可能看起來像
select
EMPNO,
DTRDate,
T1.DT_START as ’TIME IN’,
T1.DT_END as ’TIME OUT’,
CASE T2.DT_END
WHEN T2.DT_END IS NOT NULL
THEN T2.DT_END
ELSE ‘-’
END AS ‘AM OUT’,
CASE T2.DT_START
WHEN T2.DT_START IS NOT NULL
THEN T2.DT_START
ELSE ‘-’
END AS ‘AM IN’,
CASE T3.DT_END
WHEN T3.DT_END IS NOT NULL
THEN T3.DT_END
ELSE ‘-’
END AS ‘LUNCH OUT’,
CASE T3.DT_START
WHEN T3.DT_START IS NOT NULL
THEN T3.DT_START
ELSE ‘-’
END AS ‘LUNCH IN’,
CASE T4.DT_END
WHEN T4.DT_END IS NOT NULL
THEN T4.DT_END
ELSE ‘-’
END AS ‘PM OUT’,
CASE T4.DT_START
WHEN T4.DT_START IS NOT NULL
THEN T4.DT_START
ELSE ‘-’
END AS ‘PM IN’,
FROM TABLENAME AS T1
LEFT outer JOIN TABLENAME AS T2 ON T1.EMPNO == T2.EMPNO AND T1.TRANS_TYPE = ’SHIFT’ AND T2.TRANS_TYPE= ‘AMBREAK’ AND T1.TRANS_TYPE == T2.TRANS_TYPE AND T1.DTRDATE == T2.DTRDATE
LEFT OUTER JOIN TABLENAME AS T3 ON T2.EMPNO == T3.EMPNO AND T2.DTRDATE == T3.DTRDATE AND T3.TRANS_TYPE = ’LUNCH’ AND T2.TRANS_TYPE == T3.TRANS_TYPE
LEFT OUTER JOIN TABLENAME AS T4 ON T3.EMPNO == T4.EMPNO AND T4.DTRDATE == T3.DTRDATE AND T4.TRANS_TYPE = ’PMBREAK AND T3.TRANS_TYPE == T4.TRANS_TYPE
where T1.TRANS_TYPE = ’SHIFT’
1
使用CASE
聲明:
SELECT EmpNo, DTRDATE,
(CASE WHEN TRANS_TYPE = 'Shift' THEN DT_START ELSE NULL END) TimeIN,
(CASE WHEN TRANS_TYPE = 'Shift' THEN DT_END ELSE NULL END) TimeOUT,
(CASE WHEN TRANS_TYPE = 'AMBreak' THEN DT_START ELSE NULL END) AMIN,
(CASE WHEN TRANS_TYPE = 'AMBreak' THEN DT_START ELSE NULL END) AMOUT,
etc...
FROM YourTable
閱讀這個問題更多的淨空:SQL Case Statement Syntax?
0
,我遲到了,但我花了更長的時間才能找到解決辦法..
create table #temp(
empno int,
dtrdate date,
trans_type nvarchar(18),
dt_start time,
dt_end time
)
insert into #temp(empno,dtrdate,trans_type,dt_start,dt_end)
values
(28, '01/02/2017','shift','10:53:27','22:05:47'),
(28, '01/02/2017','ambreak','12:00:27','12:14:47'),
(28, '01/02/2017','lunch','16:00:27','16:05:47'),
(28, '01/03/2017','shift','12:47:27','22:47:47'),
(28, '01/03/2017','ambreak','14:02:27','14:11:47'),
(28, '01/03/2017','lunch','15:01:27','15:52:47'),
(28, '01/03/2017','pmbreak','20:32:27','20:40:47')
Select empno, dtrdate,
max(case trans_type when 'shift' then dt_start else null end) as [time in],
max(case trans_type when 'shift' then dt_end else null end) as [time out]
......
......
from #temp
group by empno, dtrdate
0
我希望它幫你
SELECT t1.EmpNo, t1.DTRDATE,
(CASE WHEN t1.DT_START is not null THEN t1.DT_START ELSE Null END) TimeIN,
(CASE WHEN t1.DT_START is not null THEN t1.DT_END ELSE Null END) TimeOUT,
(CASE WHEN t2.DT_START is not null THEN t2.DT_START ELSE Null END) AMIN,
(CASE WHEN t2.DT_START is not null THEN t2.DT_END ELSE Null END) AMOUT,
(CASE WHEN t3.DT_START is not null THEN t3.DT_START ELSE Null END) LUNCHIN,
(CASE WHEN t3.DT_START is not null THEN t3.DT_END ELSE Null END) LUNCHOUT,
(CASE WHEN t4.DT_START is not null THEN t4.DT_START ELSE Null END) PMIN,
(CASE WHEN t4.DT_START is not null THEN t4.DT_END ELSE Null END) PMOUT
FROM
(select * from Table_1 where TRANS_TYPE = 'SHIFT') AS t1 left join
(select * from Table_1 where TRANS_TYPE = 'AMBREAK') AS t2 on t1.EMPNO = t2.EMPNO and t1.DTRDATE = t2.DTRDATE left join
(select * from Table_1 where TRANS_TYPE = 'LUNCH') AS t3 on t1.EMPNO = t3.EMPNO and t1.DTRDATE = t3.DTRDATE left join
(select * from Table_1 where TRANS_TYPE = 'PMBREAK') AS t4 on t1.EMPNO = t4.EMPNO and t1.DTRDATE = t4.DTRDATE
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凡額外列是從哪裏來的? –
如果它來自另一張桌子,那麼你可以加入兩張桌子來獲得你想要的輸出。 –
沒有額外的表,我只是想重新安排它,只是爲了查看 – jessemiel