Perl語法錯誤：在操作員期望的地方發現了Bareword

Question

正如標題所示，我該如何實現這一目標？

我一直在下面的教程，但我得到一個語法錯誤：

Bareword found where operator expected at arrays_and_variables.pl line 
26, near "$2names" 
     (Missing operator before names?) syntax error at 
arrays_and_variables.pl line 26, near "$2names " Execution of 
arrays_and_variables.pl aborted due to compilation errors. 

我到目前爲止的代碼是：

@names = ('james','dylan','max'); 

# join elements of array into a schalar variable. 
$2names = join ('', @names); 
print $s2names; 

Answer 1

2names是無效的變量名。名稱不能以數字—開頭，他們必須以字母或下劃線開頭。