拆分值

Question

可能重複：
Turning a Comma Separated string into individual rows

我從存儲過程以下輸出，並想知道的價值觀分裂成多行的最佳方式。

reference name       subjects  subjectstitle 
LL9X81MT Making and Decorating Pottery F06,F27,F38  NULL 

我需要修剪逗號的主題字段，並複製三行信息，所以數據如下。

reference name       subjects  subjectstitle 
LL9X81MT Making and Decorating Pottery F06  NULL 
LL9X81MT Making and Decorating Pottery F27  NULL 
LL9X81MT Making and Decorating Pottery F38  NULL 

我正在使用MS SQL Server 2008來設置這些SP，只需要一些關於如何分割主題字段的幫助。

感謝，

Answer 1

您將要使用某種類型的表值分割功能的類似：

create FUNCTION [dbo].[Split](@String varchar(MAX), @Delimiter char(1))  
returns @temptable TABLE (items varchar(MAX))  
as  
begin  
    declare @idx int  
    declare @slice varchar(8000)  

    select @idx = 1  
     if len(@String)<1 or @String is null return  

    while @idx!= 0  
    begin  
     set @idx = charindex(@Delimiter,@String)  
     if @idx!=0  
      set @slice = left(@String,@idx - 1)  
     else  
      set @slice = @String  

     if(len(@slice)>0) 
      insert into @temptable(Items) values(@slice)  

     set @String = right(@String,len(@String) - @idx)  
     if len(@String) = 0 break  
    end 
return 
end; 

然後可以使用outer apply加入與yourtable：

select t1.reference, 
    t1.name, 
    t1.subjectstitle, 
    i.items subjects 
from yourtable t1 
outer apply dbo.split(t1.subjects, ',') i 

給出如下結果：

| REFERENCE |       NAME | SUBJECTSTITLE | SUBJECTS | 
------------------------------------------------------------------------ 
| LL9X81MT | Making and Decorating Pottery |  (null) |  F06 | 
| LL9X81MT | Making and Decorating Pottery |  (null) |  F27 | 
| LL9X81MT | Making and Decorating Pottery |  (null) |  F38 | 

見SQL fiddle with Demo

如果你想這樣做沒有分裂的功能，那麼你可以使用CTE：

;with cte (reference, name, subjectstitle, subjectitem, subjects) as 
(
    select reference, 
    name, 
    subjectstitle, 
    cast(left(subjects, charindex(',',subjects+',')-1) as varchar(50)) subjectitem, 
     stuff(subjects, 1, charindex(',',subjects+','), '') subjects 
    from yourtable 
    union all 
    select reference, 
    name, 
    subjectstitle, 
    cast(left(subjects, charindex(',',subjects+',')-1) as varchar(50)) , 
    stuff(subjects, 1, charindex(',',subjects+','), '') subjects 
    from cte 
    where subjects > '' 
) 
select reference, name, subjectstitle, subjectitem 
from cte 

見SQL Fiddle with Demo

Answer 2

這將在不分裂的功能做

SELECT T1.reference, T1.name, T2.my_Splits AS subjects, T1.subtitile 
FROM 
(
    SELECT *, 
    CAST('<X>'+replace(T.subjects,',','</X><X>')+'</X>' as XML) as my_Xml 
    FROM [yourTable] T 
) T1 
CROSS APPLY 
( 
SELECT my_Data.D.value('.','varchar(50)') as my_Splits 
FROM T1.my_Xml.nodes('X') as my_Data(D) 
) T2