簡單的Informix選擇存儲過程

Question

我試圖寫一個簡單的存儲過程，做一個SELECT語句，但它一直給我一個語法錯誤，沒有任何其他幫助，告訴我是什麼錯誤

create procedure _this_is_it(this CHAR(3), that CHAR(4), other CHAR(3)) 
foreach select * from table 
where column1 = this and 
column2 = that and 
column3 = other 
end foreach 
end procedure; 

任何理由我應該得到一個語法錯誤？

Answer 1

刪除foreach和_作爲第一個字母，在選擇結束時還添加一個;。

create procedure this_is_it(this CHAR(3), that CHAR(4), other CHAR(3)) 

select * from table 
where column1 = this and 
column2 = that and 
column3 = other; 

end procedure; 

Answer 2

如果你想，你必須foreach循環內進行一些處理SELECT INTO變量。所以，你的代碼將變成：

drop procedure if exists _this_is_it ; 
drop table if exists this_table ; 
create temp table this_table(column1 CHAR(3), column2 CHAR(4), column3 CHAR(3)) 
with no log ; 
insert into this_table values("A","B","C") ; 

create procedure _this_is_it(this CHAR(3), that CHAR(4), other CHAR(3)) 
returns CHAR(10) AS something 

define f_this CHAR(3) ; 
define f_that CHAR(4) ; 
define f_other CHAR(3) ; 

foreach 
select * into f_this, f_that, f_other 
from this_table 
where column1 = this and 
column2 = that and 
column3 = other 

return f_this||f_that||f_other WITH RESUME ; 

end foreach 
end procedure; 

grant execute on _this_is_it to public; 
execute procedure _this_is_it("A","B","C") ; 

drop procedure if exists _this_is_it ; 
drop table if exists this_table ; 

的語法foreach語句可從IBM在其Infocenter。