SQL選擇每天總計數，但按日期和小時分組（每小時運行總計）

Question

我發現了類似於我想要的東西here，但它沒有給出完全正確的輸出，而且我正在一個愚蠢的時刻，試圖想出正確的解決方案...

我們有一個AVS服務器（實時帳戶驗證服務，但這是無關緊要的），我想知道有多少請求今天（或任何其他日子），在每個小時。例如，假設在上午8點到9點之間發出了100個請求，並且在9點到10點之間發出了50個請求。輸出應該有在8AM，和在9AM，但低於我的查詢被顯示的請求的數量在每一個小時來代替。

我可以看到它爲什麼這樣做...它通過小時分組，因此它顯示我在每個小時的要求，但是這不是我想要的東西，這是每小時一個運行總計。 （所以我可以每天運行它，看看請求的數量看起來像昨天這個時間，等等......並且指出這是一個緩慢還是快速的日子。）我該怎麼做？

DECLARE @CurrentDate DATETIME = '14 nov 2014' 

SELECT 
    CAST(DateCreated AS DATE) [Date], 
    DATEPART(hour,DateCreated) [Hour], 
    COUNT(ID) [Requests] 
FROM Request 
WHERE 
    DateCreated >= @CurrentDate AND Request.DateCreated < DATEADD(DAY, 1, @CurrentDate) 
GROUP BY 
    CAST(DateCreated AS DATE), 
    DATEPART(hour, DateCreated) 
ORDER BY 
    CAST(DateCreated AS DATE) 

Answer 1

感謝您對所有的答案。雖然他們沒有做到我想要的東西，但這是我的最後一個問題，以防它可能幫助某人。答案的問題，也可能是我的問題，結果只顯示每小時的總請求數，而不是當天的最終總數。我的查詢在下面給出了每小時的請求數，以及當天的最終請求數，或者當前總數，如果是當天。

DECLARE @CurrentDate DATETIME = '17 Nov 2014' 

SELECT * FROM ( 
    SELECT DISTINCT 
     CAST(DateCreated AS DATE) [Date], 
     CASE 
      WHEN LEN(CAST(DATEPART(hour,DateCreated) AS VARCHAR)) = 1 THEN '0' + CAST(DATEPART(hour,DateCreated) AS VARCHAR) 
      ELSE CAST(DATEPART(hour,DateCreated) AS VARCHAR) 
     END + ':00:00' [Time], 
     rank() OVER (ORDER BY DATEPART(hour, DateCreated))[Requests] 
    FROM Request 
    WHERE 
     DateCreated >= @CurrentDate AND DateCreated < DATEADD(DAY, 1, @CurrentDate) 
    UNION 
    SELECT 
     CAST(@CurrentDate AS DATE), 
     CONVERT(VARCHAR(8), 
       (SELECT TOP 1 DateCreated FROM Request WHERE DateCreated >= @CurrentDate AND Request.DateCreated < DATEADD(DAY, 1, @CurrentDate) ORDER BY DateCreated DESC), 
       108), 
     (SELECT COUNT(*) from Request WHERE DateCreated >= @CurrentDate AND Request.DateCreated < DATEADD(DAY, 1, @CurrentDate)) 
     ) t 
WHERE t.Requests > 0   
ORDER BY t.Time 

今天運行查詢提供了這樣的輸出：

+------------+----------+----------+ 
| Date | Time | Requests | 
+------------+----------+----------+ 
| 2014-11-17 | 07:00:00 |  1 | 
| 2014-11-17 | 08:00:00 |  9 | 
| 2014-11-17 | 09:00:00 |  49 | 
| 2014-11-17 | 10:00:00 |  113 | 
| 2014-11-17 | 11:00:00 |  225 | 
| 2014-11-17 | 12:00:00 |  294 | 
| 2014-11-17 | 13:00:00 |  363 | 
| 2014-11-17 | 13:09:46 |  383 | 
+------------+----------+----------+ 

Answer 2

DECLARE @CurrentDate DATETIME = '14 nov 2014'; 

WITH hourValues(hourVal) as (
    select distinct cast(convert(varchar(14), @CurrentDate, 120) + '00' as datetime) 
    from [Request] 
    where datediff(day, [DateCreated], @CurrentDate) = 0) 
SELECT 
    CAST(DateCreated AS DATE) [Date], 
    hourVal, 
    COUNT(case when [DateCreated] < dateadd(hour, 1, hourVal) then 1 else null end) [Requests] 
FROM Request, hourValues 
WHERE 
    datediff(day, [DateCreated], @CurrentDate) = 0 
GROUP BY 
    CAST(DateCreated AS DATE), 
    hourVal 
ORDER BY 
    [Date], 
    HourVal 

Answer 3

下面應該工作

DECLARE @CurrentDate DATETIME = '13 nov 2014' 

SELECT DISTINCT 
    CAST(DateCreated AS DATE) [Date], 
    DATEPART(hour,DateCreated) [Hour], 
    COUNT(ID) OVER (ORDER BY DATEPART(hour, DateCreated)) 
FROM Request 
WHERE 
    DateCreated >= @CurrentDate AND DateCreated < DATEADD(DAY, 1, @CurrentDate) 
ORDER BY 
    DATEPART(hour, DateCreated) 

Answer 4

 --if you use MS SQL Server 2008 R2 or later version (2012/2014) then try this 

DECLARE @CurrentDate DATE = CONVERT(DATE, GETDATE() - 1) , --yesterday 
    @FinishDate AS DATE = CONVERT(DATE, GETDATE() + 1) --tomorrow 

SELECT DISTINCT 
     CONVERT(DATE, DateCreated) AS [Date] , 
     DATEPART(HOUR, DateCreated) AS [Hour] , 
     COUNT(ID) OVER (PARTITION BY CONVERT(DATE, DateCreated) ORDER BY DATEPART(HOUR, 
                   DateCreated)) AS [Cumulative Count] 
FROM Request 
WHERE CONVERT(DATE, DateCreated) BETWEEN @CurrentDate 
            AND  @FinishDate 
ORDER BY CONVERT(DATE, DateCreated) , 
     DATEPART(HOUR, DateCreated)