在Java中縮短數組

Question

我的代碼的一部分包含它。

public void drawBoard(){ 
    for (int i = 0; i < 8; i++){ 
     for (int j = 0; j < 8; j++){ 
      board[i][j] = null; 
     } 
    } 

    board[0][1] = new Piece(false); 
    board[1][1] = new Piece(false); 
    board[2][1] = new Piece(false); 
    board[3][1] = new Piece(false); 
    board[4][1] = new Piece(false); 
    board[5][1] = new Piece(false); 
    board[6][1] = new Piece(false); 
    board[7][1] = new Piece(false); 
} 

除了聲明每個元素的位置之外，有沒有辦法縮短它呢？

Answer 1

public void drawBoard(){ 
    for (int i = 0; i < 8; i++){ 
     for (int j = 0; j < 8; j++){ 
      board[i][j] = null; 

     } 
     board[i][1] = new Piece(false); 
    } 
} 

對於踢腿，如果您使用一維數組表示8x8板，您可以用這種方式做同樣的事情，消除一個循環。

public void drawBoard() { 
    int j = -1; 
    for (int i = 0; i < 64; i++) { 
     // j represents your "column" 
     // every 8 counts, a new column is found 
     if (i % 8 == 0) { 
      j++; 
     } 

     // for the '1' column, set your piece, else null 
     board[i] = (j == 1) ? new Piece(false) : null; 
    } 
}