如何爲我的方法獲得正確的輸出？

我想不顯示測驗，實驗室，實驗室考勤，期中考試一樣喜歡這 - 測驗：66％實驗室：88％實驗室出勤率：81％期中考試：91％決賽：不適用總體平均：85 ％。但我發現了如何爲我的方法獲得正確的輸出？

輸出：

我怎麼會得到什麼，我試圖完成正確的輸出。

import java.io.*; 
    import java.util.*; 

public class FindGrade { 
    public static final int NUM_SCORE_TYPES = 5; 

    public static void main(String[] args) { 
     Scanner scan = null; 
     int[] quizArray = null; 
     int[] labArray = null; 
     int[] attendance = null; 
     int[] midterms = null; 
     int quizgrade = 0; 
     int labgrade = 0; 
     int attendance_1 = 0; 
     int midterms_1 = 0; 
     String name; 


     try { 
      scan = new Scanner(new File("input.txt")); 
     } catch (FileNotFoundException e) { 
      e.printStackTrace(); 
      return; 
     } 

     // each iteration is for single exam type (ie: Quizzes is the 1st one) 
     for (int i = 0; i < NUM_SCORE_TYPES; i++) { 

      name = scan.next(); 
      int numScores = scan.nextInt(); 
      int maxGrade = scan.nextInt(); 

      if (name.equals("Quizzes")) { 
       quizArray = new int[numScores]; 
       readScores(quizArray, numScores, scan,maxGrade); 


      } else if (name.equals("Labs")) { 
       labArray = new int[numScores]; 
       readScores(labArray, numScores, scan,maxGrade); 

      } else if (name.equals("Lab_attendance")) { 
       attendance = new int[numScores]; 
       readScores(attendance, numScores, scan,maxGrade); 

      } else if (name.equals("Midterms")) { 
       midterms = new int[numScores]; 
       readScores(midterms, numScores, scan,maxGrade); 

      } 

     } 

    } 


    public static void readScores(int[] scoreArray, int numScores, Scanner scan, int maxGrade) { 
     for (int i = 0; i < numScores; i++) { 
      scoreArray[i] = scan.nextInt(); 
     } 
     System.out.println(average(scoreArray, numScores, maxGrade)); 
    } 

    public static int normalize(int[] scoreArray, int maxGrade) { 
     int total = 0; 
     for (int i = 0; i < scoreArray.length; i++) { 
      total += scoreArray[i]; 
     } 
     int percent = Math.round(total * 100/maxGrade); 
     return percent; 
    } 

    public static double average(double[] scoreArray, int numScores,int maxGrade) { 
     double sum = 0; 
     for (int i = 0; i < scoreArray.length; i++) { 
      sum += scoreArray[i]; 
     } 
     double average = Math.round((sum/numScores)*100/maxGrade); 

     return average;

}

輸入文件：

Quizzes 8 10 
5 8 9 10 4 0 10 7 
Labs 6 100 
95 90 100 87 63 92 
Lab_attendance 16 1 
1 1 1 0 1 1 1 1 0 1 1 1 1 0 1 1 
Midterms 2 100 
87 94 
Final 0 100

來源

2014-02-09 user124557

這裏是你修改的代碼&預期的O/P：

import java.io.*; 
import java.util.*; 

public class FindGrade { 
public static final int NUM_SCORE_TYPES = 5; 

public static void main(String[] args) { 
    Scanner scan = null; 
    String quizzes= "Quizzes"; 
    String labs= "Labs"; 
    String lab_attendance= "Lab_attendance"; 
    String midterm= "Midterms"; 
    int[] quizArray = null; 
    int[] labArray = null; 
    int[] attendance = null; 
    int[] midterms = null; 
    int quizgrade = 0; 
    int labgrade = 0; 
    int attendance_1 = 0; 
    int midterms_1 = 0; 
    String name; 


    try { 
     scan = new Scanner(new File("C://Users//Desktop//input.txt")); 
    } catch (FileNotFoundException e) { 
     e.printStackTrace(); 
     return; 
    } 

    // each iteration is for single exam type (ie: Quizzes is the 1st one) 
    for (int i = 0; i < NUM_SCORE_TYPES; i++) { 

     name = scan.next(); 
     int numScores = scan.nextInt(); 
     int maxGrade = scan.nextInt(); 

     if (name.equals("Quizzes")) { 
      quizArray = new int[numScores]; 
      readScores(quizArray, numScores, scan,maxGrade, quizzes); 


     } else if (name.equals("Labs")) { 
      labArray = new int[numScores]; 
      readScores(labArray, numScores, scan,maxGrade, labs); 

     } else if (name.equals("Lab_attendance")) { 
      attendance = new int[numScores]; 
      readScores(attendance, numScores, scan,maxGrade,lab_attendance); 

     } else if (name.equals("Midterms")) { 
      midterms = new int[numScores]; 
      readScores(midterms, numScores, scan,maxGrade, midterm); 

     } 

    } 

} 


public static void readScores(int[] scoreArray, int numScores, Scanner scan, int maxGrade, String name) { 
    for (int i = 0; i < numScores; i++) { 
     scoreArray[i] = scan.nextInt(); 
    } 
    average(scoreArray, numScores, maxGrade, name); 
} 

public static int normalize(int[] scoreArray, int maxGrade) { 
    int total = 0; 
    for (int i = 0; i < scoreArray.length; i++) { 
     total += scoreArray[i]; 
    } 
    int percent = Math.round(total * 100/maxGrade); 
    return percent; 
} 

public static double average(int[] scoreArray, int numScores,int maxGrade, String name) { 
    double sum = 0; 
    for (int i = 0; i < scoreArray.length; i++) { 
     sum += scoreArray[i]; 
    } 
    double average = Math.round((sum/numScores)*100/maxGrade); 

    System.out.println(name + ":" + average+" %"); 

    return average; 
} 
}

而結果是：

Quizzes:66.0 % 
Labs:88.0 % 
Lab_attendance:81.0 % 
Midterms:91.0 %**

來源

2014-02-09 19:16:33 VibrantVivek

如果我想包括總體平均數，我會採用與我平均方法 – user124557

@ user124557相同的方式 - 好吧，您的意思是取最終的平均值，是的，您可以使用avreage方法如明智或創建一個單獨的計算最終平均值和打印的方法。希望它有幫助！ – VibrantVivek

親愛的@ user124557如果它的工作或幫助你可以通過接受作爲答案來欣賞。謝謝。 – VibrantVivek

-2

你實際上並沒有張貼在那裏你打印什麼任何代碼，但你想要的東西可能是System.out.format()。

來源

2014-02-09 18:45:55 chrylis

我忘了添加s.o.p.我將它添加到原始代碼中。 – user124557

@ user124557不知道爲什麼有人低估了我的正確答案;它正是你需要的。 – chrylis

您需要將名稱傳遞給Average並打印名稱和分數。查看下面的固定代碼的建議，它給出你正在尋找的輸入。

import java.io.*; 
import java.util.*; 

public class FindGrade { 
public static final int NUM_SCORE_TYPES = 5; 

public static void main(String[] args) { 
    Scanner scan = null; 
    int[] quizArray = null; 
    int[] labArray = null; 
    int[] attendance = null; 
    int[] midterms = null; 
    int quizgrade = 0; 
    int labgrade = 0; 
    int attendance_1 = 0; 
    int midterms_1 = 0; 
    String name; 


    try { 
     scan = new Scanner(new File("c:\\temp\\input.txt")); 
    } catch (FileNotFoundException e) { 
     e.printStackTrace(); 
     return; 
    } 

    // each iteration is for single exam type (ie: Quizzes is the 1st one) 
    for (int i = 0; i < NUM_SCORE_TYPES; i++) { 

     name = scan.next(); 
     int numScores = scan.nextInt(); 
     int maxGrade = scan.nextInt(); 

     if (name.equals("Quizzes")) { 
      quizArray = new int[numScores]; 
      readScores(quizArray, numScores, scan,maxGrade, "Quizzes"); 


     } else if (name.equals("Labs")) { 
      labArray = new int[numScores]; 
      readScores(labArray, numScores, scan,maxGrade, "Labs"); 

     } else if (name.equals("Lab_attendance")) { 
      attendance = new int[numScores]; 
      readScores(attendance, numScores, scan,maxGrade, "Lab_attendance"); 

     } else if (name.equals("Midterms")) { 
      midterms = new int[numScores]; 
      readScores(midterms, numScores, scan,maxGrade, "Midterms"); 

     } 

    } 

} 


public static void readScores(int[] scoreArray, int numScores, Scanner scan, int maxGrade, String name) { 
    for (int i = 0; i < numScores; i++) { 
     scoreArray[i] = scan.nextInt(); 
    } 
    average(scoreArray, numScores, maxGrade, name); 
} 

public static int normalize(int[] scoreArray, int maxGrade) { 
    int total = 0; 
    for (int i = 0; i < scoreArray.length; i++) { 
     total += scoreArray[i]; 
    } 
    int percent = Math.round(total * 100/maxGrade); 
    return percent; 
} 

public static double average(int[] scoreArray, int numScores,int maxGrade, String name) { 
    double sum = 0; 
    for (int i = 0; i < scoreArray.length; i++) { 
     sum += scoreArray[i]; 
    } 
    double average = Math.round((sum/numScores)*100/maxGrade); 

    System.out.println(name + ":" + average); 

    return average; 
} 
}

然後預期輸出運行它時：

Quizzes:66.0 
Labs:88.0 
Lab_attendance:81.0 
Midterms:91.0

來源

2014-02-09 18:58:04

如何爲我的方法獲得正確的輸出？

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