失敗編輯PHP的mysqli CRUD - 未能更新數據MySQL只

我有這樣的代碼，但未能執行，請大家幫我出這個問題失敗編輯PHP的mysqli CRUD - 未能更新數據MySQL只

連接

<?php 
$servername = "localhost"; 
$username = "root"; 
$password = "pwd"; 
$database = "cece"; 

// Create connection 
$terhubung = new mysqli($servername,$username,$password, $database); 

// Check Connection 
if ($terhubung->connect_error) { 
    die ("connection failed: " . $terhubung->connect_error); 
} 
?>

這是編輯表單

<?php 
        include "conn.php"; 
        $id = $_GET['no']; 
        $query_mysql = $terhubung->query("SELECT * FROM data222 WHERE id='$id'")or die(mysql_error()); 
        $nomor = 1; 
        while($data = mysqli_fetch_array($query_mysql)){ 
        ?> 
       <form action="edit/edit_data222.php" method="post" id="demo-form2" data-parsley-validate class="form-horizontal form-label-left"> 
        <div class="form-group"> 
         <label class="control-label col-md-3 col-sm-3 col-xs-12">ID</label> 
         <div class="col-md-1 col-sm-1 col-xs-12"> 
          <input type="text" name="id" readonly="readonly" value="<?php echo $data['id']?>" class="form-control"> 
         </div> 
         </div> 

        <div class="form-group"> 
        <label class="control-label col-md-3 col-sm-3 col-xs-12" >Nama PT</label> 
        <div class="col-md-6 col-sm-6 col-xs-12"> 
         <input type="text" name="nama_pt" value="<?php echo $data['nama_pt']?>" class="form-control"> 
        </div> 
        </div> 

       <div class="form-group"> 
        <label class="control-label col-md-3 col-sm-3 col-xs-12">Barang</label> 
        <div class="col-md-4 col-sm-4 col-xs-12"> 
         <select name="brg" class="select2_single form-control" tabindex="-1"> 

         <option value="">Pilih...</option> 
         <option value="I" <?php if($data['brg'] == 'I'){ echo 'selected'; } ?> >I</option> 
         <option value="E" <?php if($data['brg'] == 'E'){ echo 'selected'; } ?> >E</option> 
         <option value="C" <?php if($data['brg'] == 'C'){ echo 'selected'; } ?> >C</option> 

         </select> 
        </div> 
        </div>  



        <div class="form-group"> 
        <label class="control-label col-md-3 col-sm-3 col-xs-12">Tipe</label> 
        <div class="col-md-2 col-sm-2 col-xs-12"> 
         <select name="jalur" class="select2_single form-control" tabindex="-1"> 
         <option value="">Jalur...</option> 
         <option value="HL" <?php if($data['jalur'] == 'HL'){ echo 'selected'; } ?> >HL</option> 
         <option value="HM" <?php if($data['jalur'] == 'HM'){ echo 'selected'; } ?> >HM</option> 
         <option value="HH" <?php if($data['jalur'] == 'HH'){ echo 'selected'; } ?> >HH</option> 
         <option value="KL" <?php if($data['jalur'] == 'KL'){ echo 'selected'; } ?> >KL</option> 
         <option value="KM" <?php if($data['jalur'] == 'KM'){ echo 'selected'; } ?> >KM</option> 
         <option value="KH" <?php if($data['jalur'] == 'KH'){ echo 'selected'; } ?> >KH</option> 
         <option value="ML" <?php if($data['jalur'] == 'ML'){ echo 'selected'; } ?> >ML</option> 
         <option value="MM" <?php if($data['jalur'] == 'MM'){ echo 'selected'; } ?> >MM</option> 
         <option value="MH" <?php if($data['jalur'] == 'MH'){ echo 'selected'; } ?> >MH</option> 
         <option value="MK" <?php if($data['jalur'] == 'MK'){ echo 'selected'; } ?> >MK</option> 
         </select> 
        </div> 
        </div> 


        <div class="form-group"> 
        <label class="control-label col-md-3 col-sm-3 col-xs-12" >No doc</label> 
        <div class="col-md-6 col-sm-6 col-xs-12"> 
         <input type="text" name="no_dok" value="<?php echo $data['no_dok']?>" class="form-control"> 
        </div> 

        <div class="col-md-3 col-sm-3 col-xs-12"> 
         <input id="tglx1" name="tgl_dok" class="date-picker form-control has-feedback-left" type="text" value="<?php echo $data['tgl_dok']?>"> 
         <span class="fa fa-calendar-o form-control-feedback left" aria-hidden="true"></span> 
        </div>      
        </div> 

        <div class="form-group"> 
        <label class="control-label col-md-3 col-sm-3 col-xs-12" >No Surat</label> 
        <div class="col-md-6 col-sm-6 col-xs-12"> 
         <input type="text" name="no_print" value="<?php echo $data['no_print']?>" class="form-control"> 
        </div> 

        <div class="col-md-3 col-sm-3 col-xs-12"> 
         <input id="tglx2" name="tgl_print" class="date-picker form-control has-feedback-left" type="text" value="<?php echo $data['tgl_print']?>"> 
         <span class="fa fa-calendar-o form-control-feedback left" aria-hidden="true"></span> 
        </div>      
        </div> 

        <!--ssssssss--> 

        <div class="ln_solid"></div> 
        <div class="form-group"> 
        <div class="col-md-6 col-sm-6 col-xs-12 col-md-offset-3"> 
         <button type="submit" class="btn btn-success">Submit</button> 
        </div> 
        </div> 
       </form> 
       <?php } ?>

這是更新代碼

<?php 

include 'conn.php'; 

$id=$_POST['id']; 
$nama_pt=$_POST['nama_pt']; 
$brg=$_POST['brg']; 
$jalur=$_POST['jalur']; 
$no_dok=$_POST['no_dok']; 
$tgl_dok=$_POST['tgl_dok']; 
$no_print=$_POST['no_print']; 
$tgl_print=$_POST['tgl_print']; 

mysqli_query($terhubung, "UPDATE data222 SET 
id='$id', 
nama_pt='$nama_pt', 
brg='$brg', 
jalur='$jalur', 
no_dok='$no_dok', 
tgl_dok='$tgl_dok', 
no_print='$no_print', 
tgl_print='$tgl_print', 
WHERE id ='$id' 
"); 
?>

當我點擊提交時，mysql中沒有改變。什麼是錯誤

來源

2017-05-26 dwic

即使喲你的代碼運行正常，這也是危險的，它很容易受到SQL注入攻擊。執行代碼時請提供更多信息 –

您有多少文件編輯窗體？ –

該代碼無效。我使用類似的，但它運行。我該怎麼做。我只使用本地連接。 – dwic

嘗試，如果將工作改變這種

<button type="submit" class="btn btn-success">Submit</button>

到

<input type="submit" name="update" class="btn btn-success" />

和更改更新代碼

<?php 
if (isset($_POST['update'])){ 
copy paste the code you write in update 
}

來源

2017-05-26 03:25:33

謝謝，但它仍然沒有工作 – dwic

嘗試刪除id ='$ id';在更新查詢 –

沒有工作，順便說一句我用bootstrap的形式 – dwic

嘗試編輯把變量{}與查詢

來源

2017-05-26 03:46:34

失敗編輯PHP的mysqli CRUD - 未能更新數據MySQL只

回答

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