如何爲Object類型的屬性使用ShouldSerialize [MemberName]（）方法？

Question

我試圖防止在Newtonsoft.Json中使用ShouldSerialize方法將沒有新值賦給它的屬性的類型對象的屬性。但我不知道如何實現它，所以請幫我解決這個...

下面是示例代碼

public class Sample1 
{ 
    public String name{get;set;} 
    public int Id{get;set;}; 
} 

這是包含上述類作爲它的屬性

我的一個類

public class Container 
{ 
    public String Cname{get;set;} 
    public Sample1 Sample{get;set;}; 

    public bool ShouldSerializeSample() 
    { 
     //What should I write here to prevent the Sample property from being serialized when its properties are assigned no new values. 

    } 
} 

Answer 1

鑑於你的例子類，我想你，你正在尋找的東西是這樣的：

public bool ShouldSerializeSample() 
{ 
    return (Sample != null && (Sample.Id != 0 || Sample.name != null)); 
} 

這是一個工作演示：

class Program 
{ 
    static void Main(string[] args) 
    { 
     List<Container> list = new List<Container> 
     { 
      new Container 
      { 
       Cname = "Will serialize Sample because it has a name", 
       Sample = new Sample1 { name = "sample 1" } 
      }, 
      new Container 
      { 
       Cname = "Will serialize Sample because it has a non-zero Id", 
       Sample = new Sample1 { Id = 2 } 
      }, 
      new Container 
      { 
       Cname = "Will serialize Sample because it has a name and an Id", 
       Sample = new Sample1 { name = "sample 3", Id = 3 } 
      }, 
      new Container 
      { 
       Cname = "Will not serialize Sample because it has default values", 
       Sample = new Sample1() 
      }, 
      new Container 
      { 
       Cname = "Will not serialize Sample because it is null", 
       Sample = null 
      } 
     }; 

     string json = JsonConvert.SerializeObject(list, Formatting.Indented); 
     Console.WriteLine(json); 
    } 
} 

public class Sample1 
{ 
    public String name { get; set; } 
    public int Id { get; set; } 
} 

public class Container 
{ 
    public String Cname { get; set; } 
    public Sample1 Sample { get; set; } 

    public bool ShouldSerializeSample() 
    { 
     return (Sample != null && (Sample.Id != 0 || Sample.name != null)); 
    } 
} 

這裏是輸出：

[ 
    { 
    "Cname": "Will serialize Sample because it has a name", 
    "Sample": { 
     "name": "sample 1", 
     "Id": 0 
    } 
    }, 
    { 
    "Cname": "Will serialize Sample because it has a non-zero Id", 
    "Sample": { 
     "name": null, 
     "Id": 2 
    } 
    }, 
    { 
    "Cname": "Will serialize Sample because it has a name and an Id", 
    "Sample": { 
     "name": "sample 3", 
     "Id": 3 
    } 
    }, 
    { 
    "Cname": "Will not serialize Sample because it has default values" 
    }, 
    { 
    "Cname": "Will not serialize Sample because it is null" 
    } 
]