-1
我有6 <select>
框。我正在根據<select>
框進行報告。我所做的就是創建一個表單並將其設置爲GET,然後通過下一頁的$ _GET方法獲取這些值。像如何使PHP中的下拉式基本MySQL查詢
<form method="get" action="report.php">
<select name="select1">
<option value="none">Select value</option>
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
</select>
<select name="select2">
<option value="none">Select value</option>
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
</select>
<select name="select3">
<option value="none">Select value</option>
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
</select>
.....................
</form>
這裏是PHP代碼。 (這些都是樣本數據:P)試圖告訴你人們我的問題。我得到,如果它的價值等於沒有或沒有做這一切值的檢查等
if(
$cby == "none"
&& $crequirment == "none"
&& $cdepartment == "none"
&& $period == "none"
&& $ccontact == "none"
&& $cattend == "none"
)
{
$query = mysqli_query($db, "SELECT * FROM customer");
}
else if (
$cby != "none"
&& $crequirment == "none"
&& $cdepartment == "none"
&& $period == "none"
&& $ccontact == "none"
&& $cattend == "none"
)
{
$query = mysqli_query($db, "SELECT * FROM customer WHERE cby = $cby");
}
else if (
$cby == "none"
&& $crequirment == "none"
&& $cdepartment != "none"
&& $period == "none"
&& $ccontact == "none"
&& $cattend == "none")
{
$query = mysqli_query($db, "SELECT * FROM customer WHERE cdepartment = $cdepartment");
}
else if..........
我想是使盡可能簡單。我應該採用什麼方法來採用它?
您的問題不明確。你需要哪些幫助? – sanders