Spotipy：如何從播放列表中讀取超過100首曲目

Question

我正在嘗試使用Spotipy library for python來拉取某個播放列表中的所有曲目。

無論參數限制如何，user_playlist_tracks函數都限制爲100個軌道。該Spotipy文檔描述爲：

user_playlist_tracks(user, playlist_id=None, fields=None, limit=100, offset=0, market=None)

Get full details of the tracks of a playlist owned by a user.

Parameters:

• user
• the id of the user playlist_id
• the id of the playlist fields
• which fields to return limit
• the maximum number of tracks to return offset
• the index of the first track to return market
• an ISO 3166-1 alpha-2 country code.

與Spotify的認證後，我目前使用的是這樣的：

username = xxxx 
playlist = #fromspotipy 
sp_playlist = sp.user_playlist_tracks(username, playlist_id=playlist) 
tracks = sp_playlist['items'] 
print tracks 

有沒有辦法返回超過100首曲目？我試着在函數參數中設置limit = None，但是它返回一個錯誤。

Answer 1

許多spotipy方法返回分頁結果，所以你必須通過他們滾動查看不僅僅是最大極限。我遇到這個最經常收集時播放列表的全程跟蹤上市，並因此創造了一個自定義的方法來處理這個問題：

def get_playlist_tracks(username,playlist_id): 
    results = sp.user_playlist_tracks(username,playlist_id) 
    tracks = results['items'] 
    while results['next']: 
     results = sp.next(results) 
     tracks.extend(results['items']) 
    return tracks 

Answer 2

以下是在spotipy中使用的user_playlist_tracks模塊。 （注意它默認爲100限制）。

嘗試將限制設置爲200

def user_playlist_tracks(self, user, playlist_id = None, fields=None, 
    limit=100, offset=0): 
    ''' Get full details of the tracks of a playlist owned by a user. 

     Parameters: 
      - user - the id of the user 
      - playlist_id - the id of the playlist 
      - fields - which fields to return 
      - limit - the maximum number of tracks to return 
      - offset - the index of the first track to return 
    ''' 
    plid = self._get_id('playlist', playlist_id) 
    return self._get("users/%s/playlists/%s/tracks" % (user, plid), 
       limit=limit, offset=offset, fields=fields)