ORA-01858：試圖插入時間戳時出錯（0）列

Question

我在下文提到的格式的數據，當我試圖插入到表中我得到錯誤

ORA-01858: a non-numeric character was found where a numeric was expected 

我怎樣才能順利地插入記錄到表中？

create table mytab (dt timestamp(0)); 

Insert into mytab 
    (dt) 
Values 
    (TO_TIMESTAMP('16/JUL/13 2:53:08. PM','DD/MON/YY fmHH12fm:MI:SS.FF AM')); 

Answer 1

你需要指定零小數秒。這是你的錯誤：

SQL> create table mytab (dt timestamp(0)); 

Table created. 

SQL> Insert into mytab 
    (dt) 
Values 
    (TO_TIMESTAMP('16/JUL/13 2:53:08. PM','DD/MON/YY fmHH12fm:MI:SS.FF AM')); 2 3 4 
    (TO_TIMESTAMP('16/JUL/13 2:53:08. PM','DD/MON/YY fmHH12fm:MI:SS.FF AM')) 
       * 
ERROR at line 4: 
ORA-01858: a non-numeric character was found where a numeric was expected 

SQL> 

讓我們來解決輸入

SQL> ed 
Wrote file afiedt.buf 

    1 Insert into mytab 
    2  (dt) 
    3 Values 
    4* (TO_TIMESTAMP('16/JUL/13 2:53:08.00 PM','DD/MON/YY fmHH12fm:MI:SS.FF AM')) 
SQL> r 
    1 Insert into mytab 
    2  (dt) 
    3 Values 
    4* (TO_TIMESTAMP('16/JUL/13 2:53:08.00 PM','DD/MON/YY fmHH12fm:MI:SS.FF AM')) 

1 row created. 

SQL> 

所以，即使您指定一個零精度的時間戳，您輸入仍然需要相匹配的面具。這意味着您需要有.00以匹配.FF。

可替換地，不打擾包括秒的小數部分在所有：

SQL> ed 
Wrote file afiedt.buf 

    1 insert into mytab 
    2  (dt) 
    3 Values 
    4* (TO_TIMESTAMP('16/JUL/13 2:53:08 PM','DD/MON/YY fmHH12fm:MI:SS AM')) 
SQL> r 
    1 insert into mytab 
    2  (dt) 
    3 Values 
    4* (TO_TIMESTAMP('16/JUL/13 2:53:08 PM','DD/MON/YY fmHH12fm:MI:SS AM')) 

1 row created. 

SQL> 

---

順便提及，請注意，時間戳（0）將圓任何小數秒，在半秒四捨五入。這個問題的重要程度取決於你如何填寫專欄以及時間需要多準確。

Answer 2

你有一個「。」分鐘

之後這部作品

select TO_TIMESTAMP('16/JUL/13 2:53:08 PM','DD/MON/YY fmHH12fm:MI:SS.FF AM') 
from dual 

Answer 3

你需要第二部分：

Insert into mytab(dt) 
Values 
    (TO_TIMESTAMP('16/JUL/13 2:53:08.00 PM','DD/MON/YY fmHH12fm:MI:SS.FF AM'));