如何從NSString獲取特定的字符串？

Question

我有一個字符串，如：

亞硝酸鈉E250是一種食品添加劑，讓醃肉， 如火腿E103，臘肉，熱狗，法蘭克福香腸，薰魚 E1255醃牛肉，特有的紅色和香味。

我需要的元素的一個NSArray：E250，E103，E1255從上面的文字和我的預定義的NSArray（E100，E101，E1500 ...）比較元素 是否有任何如何做到這一點？

Answer 1

正如你所說你想要與你現有的數組元素進行比較。所以，你可以做以下..

NSArray *array = @[@"E100", @"E250", @"E103", @"E200", .....]; 
NSString *myString = @"Sodium Nitrite E250 is a food additive that gives cured meats, such as ham E103, bacon, hot dogs, frankfurters, smoked fish E1255 corned beef, their characteristic red colour and flavour."; 

[array enumerateObjectsUsingBlock:^(NSString *objectString, NSUInteger idx, BOOL *stop) { 
    if([myString rangeOfString:objectString].location != NSNotFound) { 
     NSLog(@"%@ - found", objectString); 
    } 
    else { 
     NSLog(@"%@ - Not found", objectString); 
    } 
}]; 

Answer 2

而是提取，從文本字符串，我建議你從你的陣列發現的模板一樣的：

NSString *input = @"Sodium Nitrite E250 is a food additive ..."; 
for (NSString *str in @[ @"E100", @"E101", @"E1500" ]) 
    if ([input rangeOfString:str].location != NSNotFound) { 
     // do something 
    } 

Answer 3

嘗試使用此代碼

NSArray *ary = [NSArray arrayWithObjects:@"E250", nil]; // String Data to find in String 
NSMutableArray *aryFoundData = [[NSMutableArray alloc]init]; 

for (int i=0; i<ary.count; i++) { 
    NSString *str = @"Your String E250"; 
    if ([str containsString:[ary objectAtIndex:i]]) { 
     [aryFoundData addObject:[ary objectAtIndex:i]]; 
    } 
} 

// Now aryFoundData contains all the data which are available in string 

希望這會幫助你。

Answer 4

看看這樣：

NSString *testString = @"Sodium Nitrite E250 is a food additive that gives cured meats, such as ham E103, bacon, hot dogs, frankfurters, smoked fish E1255 corned beef, their characteristic red colour and flavour."; 

NSRegularExpression *regex = [[NSRegularExpression alloc] initWithPattern:@"E\\d+" options:0 error:nil]; 

[regex enumerateMatchesInString:testString options:0 range:NSMakeRange(0, testString.length) usingBlock:^(NSTextCheckingResult *result, NSMatchingFlags flags, BOOL *stop) { 
    NSLog(@"%@", [testString substringWithRange:result.range]); 
}]; 

它記錄以下：

2015-05-05 15：12：55.898標籤[3649：339896] E250

2015-05-05 15：12：55.898 Label [3649：339896] E103

2015-05-05 15:12 ：55.898標籤[3649：339896] E1255

Answer 5

請嘗試下面的邏輯可能是你的問題由此解決。

NSMutableArray *ar = [NSMutableArray new]; 
NSString *str = @"Sodium Nitrite E250 is a food additive that gives cured meats, such as ham E103, bacon, hot dogs, frankfurters, smoked fish E1255 corned beef, their characteristic red colour and flavour."; 

NSArray * words = [str componentsSeparatedByCharactersInSet:[NSCharacterSet whitespaceCharacterSet]]; 
for (NSString * word in words) { 
    if ([word length] > 0) { 
     NSString * firstLetter = [word substringToIndex:1]; 
     if ([firstLetter isEqualToString:@"E"]) { 
      [ar addObject:word]; 
     } 
    } 
} 
NSLog(@"%@",ar); 

Answer 6

您可以從NSString獲取特定的關鍵字，並做下面的事情將它們添加到NSMutableArray。

NSString* strText = @"Sodium Nitrite E250 is a food additive that gives cured meats, such as ham E103, bacon, hot dogs, frankfurters, smoked fish E1255 corned beef, their characteristic red colour and flavour."; 
    __block NSMutableArray* arrayStoreRange = [NSMutableArray new]; 

    //To Find Image from HTML string and add renge in NSMutableArray 
    //width 
    NSRegularExpression* tableRegex = [[NSRegularExpression alloc] initWithPattern:@"E\\w*\\d" options:0 error:NULL] ; 
    [tableRegex enumerateMatchesInString:strText options:0 range:NSMakeRange(0, [strText length]) usingBlock:^(NSTextCheckingResult *match, NSMatchingFlags flags, BOOL *stop){ 

     [arrayStoreRange addObject:[strText substringWithRange:match.range]]; 

    }]; 

    NSLog(@"Output : %@",arrayStoreRange); 

    for (NSString *str in arrayStoreRange){ 

     if ([yourArray containsObject:str]) { 
      // do something 
      NSLog(@"Object found"); 
     } 
     else{ 
      NSLog(@"Object not found"); 
     } 
    } 

輸出：

Output : (
    E250, 
    E103, 
    E1255 
) 

希望這有助於你。