從NSString獲取子字符串直到到達特定單詞

Question

讓我們說我有這NSString：@"Country Address Tel:number"。 如何才能獲得Tel之前的子字符串？ （國家地址） 然後我怎麼做才能得到Tel之後的子字符串？ （數字）

Answer 1

使用NSScanner：

NSString *string = @"Country Address Tel:number"; 
NSString *match = @"tel:"; 
NSString *preTel; 
NSString *postTel; 

NSScanner *scanner = [NSScanner scannerWithString:string]; 
[scanner scanUpToString:match intoString:&preTel]; 

[scanner scanString:match intoString:nil]; 
postTel = [string substringFromIndex:scanner.scanLocation]; 

NSLog(@"preTel: %@", preTel); 
NSLog(@"postTel: %@", postTel); 

的NSLog輸出：

preTel：國家地址
postTel：數

Answer 2

最簡單的方法是，如果你知道的分隔符，（如果它總是:），您可以使用此：

NSArray *substrings = [myString componentsSeparatedByString:@":"]; 
NSString *first = [substrings objectAtIndex:0]; 
NSString *second = [substrings objectAtIndex:1]; 

，將您的字符串分割成兩個部分，併爲您的數組每個子

Answer 3

這裏是zaph的答案，我已經成功地實施的延伸。

-(NSString*)stringBeforeString:(NSString*)match inString:(NSString*)string 
{ 
     if ([string rangeOfString:match].location != NSNotFound) 
     { 
      NSString *preMatch; 

      NSScanner *scanner = [NSScanner scannerWithString:string]; 
        [scanner scanUpToString:match intoString:&preMatch]; 

      return preMatch; 
     } 
     else 
     { 
      return string; 
     } 
} 

-(NSString*)stringAfterString:(NSString*)match inString:(NSString*)string 
{ 
     if ([string rangeOfString:match].location != NSNotFound) 
     { 
      NSScanner *scanner = [NSScanner scannerWithString:string]; 

      [scanner scanUpToString:match intoString:nil]; 

      NSString *postMatch; 

      if(string.length == scanner.scanLocation) 
      { 
        postMatch = [string substringFromIndex:scanner.scanLocation]; 
      } 
      else 
      { 
        postMatch = [string substringFromIndex:scanner.scanLocation + match.length]; 
      } 

      return postMatch; 
     } 
     else 
     { 
      return string; 
     } 
}