SQL Count/order in order子句

我正在爲我正在使用的工具的「排行榜」工作，我需要將一些數字合併在一起，並獲得多行記錄的計數。SQL Count/order in order子句

你會在這個存儲過程中看到的是我試圖通過2列的總和來排序記錄。

有關如何完成此任務的任何提示？

AS 
BEGIN 
SET NOCOUNT ON; 
     BEGIN 
      SELECT DISTINCT(whoAdded), 
        count(tag) as totalTags, 
        count(DISTINCT data) as totalSubmissions 
      FROM Tags_Accounts 
      GROUP BY whoAdded 
      ORDER BY SUM(totalTags + totalSubmissions) DESC 
      FOR XML PATH ('leaderboard'), TYPE, ELEMENTS, ROOT ('root'); 
     END 
END

來源

2013-11-23 SBB

你得到的錯誤是什麼？ – MusicLovingIndianGirl

列名'totalTags'無效。和totalSubmissions – SBB

是的，你得到這些錯誤，因爲'totalTags'和'totalSubmissions'僅僅是別名 – MusicLovingIndianGirl

你可以把它在一個派生表做到這一點：

SELECT * 
FROM (
    SELECT DISTINCT(whoAdded) AS whoAdded, 
     count(tag) as totalTags, 
     count(DISTINCT data) as totalSubmissions 
    FROM Tags_Accounts 
    GROUP BY whoAdded 
    ) a 
ORDER BY totalTags + totalSubmissions DESC 
FOR XML PATH ('leaderboard'), TYPE, ELEMENTS, ROOT ('root')

或者，您也可以通過聚集命令，但我覺得上面是有點清潔/冗餘少：

SELECT DISTINCT(whoAdded) as whoAdded, 
    count(tag) as totalTags, 
    count(DISTINCT data) as totalSubmissions 
FROM Tags_Accounts 
GROUP BY whoAdded 
ORDER BY SUM(count(tag) + count(DISTINCT data)) DESC 
FOR XML PATH ('leaderboard'), TYPE, ELEMENTS, ROOT ('root')

來源

2013-11-23 04:36:38

第一個返回無效的列名'totalTags'。列名'totalSubmissions'無效。 – SBB

內部的'SELECT'工作嗎？如果不是，你會得到什麼錯誤？ –

是的，內部的工作正常 – SBB

SET NOCOUNT ON; 
     BEGIN 
      ;WITH CTE AS(
      SELECT DISTINCT(whoAdded), 
        count(tag) as totalTags, 
        count(DISTINCT data) as totalSubmissions 
      FROM Tags_Accounts 
      GROUP BY whoAdded) 
      SELECT * FROM CTE 
      ORDER BY SUM(totalTags + totalSubmissions) DESC 
      FOR XML PATH ('leaderboard'), TYPE, ELEMENTS, ROOT ('root'); 
     END 
END

來源

2013-11-23 04:38:32 Raj

不要使用SUM()，只需使用+添加的值，只不過是你se表達式而不是列別名：

ORDER BY count(*) + count(DISTINCT data) DESC

來源

2013-11-23 04:53:43 Bohemian

SQL Count/order in order子句

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